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Nice Question... CR Question testing PS

by theCodeToGMAT » Thu Sep 19, 2013 11:59 pm
In Patton City, days are categorized as having heavy rainfall (more than two inches), moderate rainfall (more than one inch, but no more than two inches), light rainfall (at least a trace, but no more than one inch), or no rainfall. In 1990, there were fewer days with light rainfall than in 1910 and fewer with moderate rainfall, yet total rainfall for the year was 20 percent higher in 1990 than in 1910. If the statements above are true, then it is also possible that in Patton City
A. the number of days with heavy rainfall was lower in 1990 than in 1910
B. the number of days with some rainfall, but no more than two inches, was the same in 1990 as in 1910
C. the number of days with some rainfall, but no more than two inches, was higher in 1990 than in 1910
D. the total number of inches of rain that fell on days with moderate rainfall in 1990 was more than twice what it had been in 1910
E. the average amount of rainfall per month was lower in 1990 than in 1910

OA after some posts :)
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by vinay1983 » Fri Sep 20, 2013 1:24 am
I feel it should be D.

To supplement my point, We need to have more rainy days in 1990 than in 1910 or we need to have more rain per day.

Of all the options only D gives one of the above points.

Hence D. Though the question appears to be "quant" based(it is to some extent), but it can be solved through reasoning too!

I hope I am clear. Rich has done a good job though!
Last edited by vinay1983 on Fri Sep 20, 2013 9:24 pm, edited 1 time in total.
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by theCodeToGMAT » Fri Sep 20, 2013 1:37 am
vinay1983 wrote:I feel it should be D
"yet total rainfall for the year was 20 percent higher in 1990 than in 1910"

This contradicts [D] since the denominator is unchanged from "12".
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by [email protected] » Fri Sep 20, 2013 1:01 pm
Hi All,

This CR question is an inference question; inference questions are some of the toughest questions you'll face in the Verbal section.

The "key" to solving it is to recognize that there are two pieces to the data:

1) The number of days that a particular type/range of rain fell.
2) The number of inches of rain that fell

To get you thinking in the necessary way, consider this:

Moderate rain is defined as 1-2 inches of rain
10 days of moderate rain MIGHT HAVE fewer total inches of rain than 9 days of moderate rain that happen at another time. It could be that the 10 days totaled 10 inches of rain while the 9 days totaled 18 inches of rain.

The prompt tells us that 1990 had fewer DAYS of moderate/light rain than 1910 AND that TOTAL INCHES of rain were higher in 1990 than 1910. There are only 2 ways for all of this to happen:

1) 1990 had more rain than 1910 (on the heavy days)
2) Each day of rain in 1990 was at the "high end" of the range while each day in 1910 was at the "low end" of the range.

Final Answer: A

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Rich
Last edited by [email protected] on Sat Sep 21, 2013 10:24 am, edited 1 time in total.
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by lunarpower » Sat Sep 21, 2013 7:15 am
This problem is certainly interesting, but it's not representative of the GMAT. The GMAT would not contain a critical reasoning question that requires this much mathematical work.

When CR problems involve statistics, you'll almost never have to think about any mathematics beyond ...
... this thing is greater/less than that thing
... group statistics vs. individual statistics
... rates per unit vs. absolute numbers (e.g., "# crimes" vs. "# crimes per capita")
... averages vs. specific data points
... what will cause numbers (especially averages, percentages, and rates) to become bigger or smaller

That's pretty much it. The verbal section is the verbal section, and the math section is the math section. (If there were this much overlap between the two, there'd be no point in giving separate scores!)
Ron has been teaching various standardized tests for 20 years.

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by theCodeToGMAT » Sat Sep 21, 2013 8:25 am
I answered this Question [A].

My Reasoning is as follows:


Heavy Rainfall(HR) = 2+ inches
Moderate Rainfall(MR)= 1-2 inches
Light Rainfall(LR) = 0-1 inches
No Rain(NR) = 0

1990 --> Comparatively Fewer (LR=4) & (MR=5)
1910 --> Comparatively Higher LR=6 & MR=7

[4,5,6,7 are assumed DAYS values]

YET, Total Rainfall in 1990 is higher ----- POINT OF CONSIDERATION.... "TOTAL RAINFALL" and not "TOTAL DAYS"

Total Rainfall DAYS(TRD) = HR(heavy rainfall) + MR + LR

TRD of 1990 > TR of 1910
4 + 5 + X > 6 + 7 + Y
So, X>Y..

Total Rainfall = inches * days....

Now, assume in 1990 total days of rainfall 5 with 5 inches of rain = Total Rainfall 25
and, assume in 1910 total days of rainfall 10 with 2 inches of rain = Total Rainfall 20

Hence, [A] holds!!!
---------------------------------------

[D]cannot be correct ... since..

Using the above example only...

MR in 1990 --> Least = 5 * 1 = 5 .... Maximum = 5*2= 10 inches
MR in 1910 --> Least = 7 * 1 = 7 .... Maximum = 7*2= 14 inches

So, for any value for MR in 1990 and 1910.. we cannot have:: MR of 1990>2*MR of 1910.

hence, WRONG!.
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