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desiguy Just gettin' started!
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Posted: Tue Jul 22, 2008 4:09 am Post subject: last day queries !! thanks |
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If n is a positive integer and the product of all the intergers from 1 to n, inclusive is 990, what is the least possible value of n ?
choice:
10 or 11
Ans: is 11.
My answer is 10 because if the integers are say (1 and 10), it meets the criteria above !! |
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VP_Tatiana GMAT Instructor

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Posted: Tue Jul 22, 2008 12:43 pm Post subject: |
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I'm not sure I understand the question correctly.
The product of all the numbers from 1 to 6 inclusive is 720, and the product of all the numbers from 1 to 7 inclusive is 5040. So, it does not seem that there exists an n such that the product of the numbers from 1 to n equals 990.
Is there an "answer does not exist" answer choice?
Tatiana _________________ Tatiana Becker | GMAT Instructor | Veritas Prep | Elite GMAT Prep and Admissions Consulting
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parallel_chase GMAT Titan
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Posted: Tue Jul 22, 2008 1:40 pm Post subject: |
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DUDE you have made the same mistake while re posting the question.
Here is the actual question.
If n is a positive integer and the product of all the integers from 1 to n, inclusive, is a multiple of 990, what is the least possible value of n ?
If I take you answer which is 10
Then, what the question stem means is 10! is a multiple of 990.
10! = 10*9*8*7*6*5*4*3*2*1=3628800
990 = 9*10*11
I'll rephrase the question for you.
Is 3628800 a multiple of 990?
The answer is no if n = 10, simply because n! which is 10! does not have 11
Now lets look at 11
11! = 11*10*9*8*7*6*5*4*3*2*1
990 =9*10*11
In this case answer is yes 11! is a multiple of 990.
In the test all you have to do is look at the prime factors.
if x is a multiple of y, then x should have all the prime factors of y, but it is not necessary for y to have all the prime factors of x.
I hope this clears everything. Let me know if you still have any doubts.
All the Best. |
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gmatutor Just gettin' started!
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Posted: Tue Jul 22, 2008 5:10 pm Post subject: Prime factor |
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Prime factor 990.
990 = 2 X 5 X 3^2 X 11
Since the largest prime factor of 990 is 11, choose 11 it must be the least possible value for n. |
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egybs Really wants to Beat The GMAT!
Joined: 14 May 2008 Posts: 176
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Posted: Tue Jul 22, 2008 8:33 pm Post subject: Re: Prime factor |
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| gmatutor wrote: | Prime factor 990.
990 = 2 X 5 X 3^2 X 11
Since the largest prime factor of 990 is 11, choose 11 it must be the least possible value for n. |
While, that's right in this case, it isn't universally correct...
For example, if we were doing the same question but for the number 1920:
1920 = 2^7*3*5
In this case, 5 is the largest prime factor, but 5! would not be the appropriate answer.
We'd need to make sure that all of the prime factors are represented so:
2*3*4*5*6*7*8 or 8! would be the right answer. |
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gmatutor Just gettin' started!
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Posted: Wed Jul 23, 2008 2:09 pm Post subject: |
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Absolutely!
Forgive my imprecise language. |
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egybs Really wants to Beat The GMAT!
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Posted: Wed Jul 23, 2008 2:11 pm Post subject: |
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You're forgiven!  |
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