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kulksnikhil
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 Posted: Mon Nov 27, 2006 8:46 am Post subject: tenth digit in decimal representation |
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In the decimal representation of x, where 0< x< 1, is the tenths digit of x nonzero?
1) 16x is an integer
2) 8x is an integer
The right answer is B
Can anybody help solve this? What is 10ths digit in decimal representation?
e.g. in 0.502, 0 is in tenth's digit place? |
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gmat_enthus
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| Posted: Mon Nov 27, 2006 2:46 pm Post subject: |
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There is a difference between tenth and tens digit.
71.234
tenth digit = 2
units digit = 1
tens digit = 7
Hope this helps
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gmat_enthus
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| Posted: Mon Nov 27, 2006 2:49 pm Post subject: Re: tenth digit in decimal representation |
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| kulksnikhil wrote: | In the decimal representation of x, where 0< x< 1, is the tenths digit of x nonzero?
1) 16x is an integer
2) 8x is an integer
The right answer is B
Can anybody help solve this? What is 10ths digit in decimal representation?
e.g. in 0.502, 0 is in tenth's digit place? |
0<x<1
1. 16x is an integer => x could 1/16, 2/16 ...... 15/16. For some of them tenths digit is 0 for others its non-zero.
2] 8x is an integer => x could be 1/8, 2/8 .... 7/8. For all of these tenths digit is never 0. "NO" to question. So sifficient
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kulksnikhil
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| Posted: Mon Nov 27, 2006 7:40 pm Post subject: Re: tenth digit in decimal representation |
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| gmat_enthus wrote: | | kulksnikhil wrote: | In the decimal representation of x, where 0< x< 1, is the tenths digit of x nonzero?
1) 16x is an integer
2) 8x is an integer
The right answer is B
Can anybody help solve this? What is 10ths digit in decimal representation?
e.g. in 0.502, 0 is in tenth's digit place? |
0<x<1
1. 16x is an integer => x could 1/16, 2/16 ...... 15/16. For some of them tenths digit is 0 for others its non-zero.
2] 8x is an integer => x could be 1/8, 2/8 .... 7/8. For all of these tenths digit is never 0. "NO" to question. So sifficient |
that's a sound reasoning...thanks. |
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rajs.kumar
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| Posted: Tue Nov 28, 2006 12:53 pm Post subject: |
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the final remainder (which leads to the tenths decimal value) when divided by 8 will always have a quotient >= 1 (since 8 < 10). On the other hand for 16 it could be >= 0 (since 16 > 10).
So B is sufficient. |
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