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How to solve this question

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Newbie | Next Rank: 10 Posts
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How to solve this question

by jcovarrubiasu » Tue Jul 24, 2007 6:22 am
If wx = y, What is the value of xy?

(1) ... WX^2 = 16

(2) ... Y = 4


Thanks for your support!

Jorge.
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Re: How to solve this question

by Sadowski » Tue Jul 24, 2007 6:37 am
jcovarrubiasu wrote:If wx = y, What is the value of xy?

(1) ... WX^2 = 16

(2) ... Y = 4


Thanks for your support!

Jorge.
First, statement (1):

y=w*x, so y*x=w*x*x=wx^2

Statement (1) is sufficient. We know that xy=wx^2=16

Now, statement (2):

y=4

We don't know what x equals, so statement (2) is NOT sufficient.

Answer is A.
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by jcovarrubiasu » Tue Jul 24, 2007 6:51 am
Thanks. So, basicly you have to multiply (y = wx) with "x" in both sides of the equation so this is not affected, then it gives wx^2 and that is on sufficient for ... (1)

I did not notice this before... Thanks you!!!

Jorge.
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