If the average (arithmetic mean) of the assessed values
of x houses is $212,000 and the average of the assessed
values of y other houses is $194,000, what is the average
of the assessed values of the x+y houses?
(1) x+y=36
(2) x=2y
I chose B, but surprisingly it turned out to be C. Clueless:)
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DS - Set 25 Math
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mschling52
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simplythebest
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I think the answer should be C.
WE need
($212,000*x + $194,000y) / x + y
and only with both the statements we can exactly find the assessed values of X+Y
WE need
($212,000*x + $194,000y) / x + y
and only with both the statements we can exactly find the assessed values of X+Y
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mschling52
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You are right, that is the formula we need to solve, but if we know just (2) then that formula becomes
(212,000(2y) + 194,000y)/((2y)+y)
= (618,000y)/(3y) = 206,000
(212,000(2y) + 194,000y)/((2y)+y)
= (618,000y)/(3y) = 206,000
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simplythebest
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Grr..Silly mistake...yup...It should be B...think i should write "Read questions carefully" a 1000 times imposition..
Thanks Mate !!!
Thanks Mate !!!
