Hi guys,
Can somebody explain it to me please.
Is x > y ?
1) 9x=4y
2)x > -y
Thanks a lot [/quote]
Positive/Negative Number properties
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Wouldn't it be E because:2008 wrote:9x=4y is sufficient to answer, hence either A or D
x>-y is not sufficient, hence A.
9x = 4y ----> x = (4/9)y
here when x = -4/9 y= -1 x> y
when x = 4/9 y=1 x<y
therefore A is not sufficient.
B is also not sufficient
Thus, E.
What's the oA?
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The answer should be E.
Statement I
9x=4y
x=4
y=9
36=36, x<y
x=-4
y=-9
-36 = -36, x>y
Hence Insufficient.
Statement II
x>-y
It does not tell us anything about positive y, therefore insufficient.
Hence the answer is E.
Whats the OA?
Statement I
9x=4y
x=4
y=9
36=36, x<y
x=-4
y=-9
-36 = -36, x>y
Hence Insufficient.
Statement II
x>-y
It does not tell us anything about positive y, therefore insufficient.
Hence the answer is E.
Whats the OA?
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Hi guys it is me again.
Thanks for all the answers and I also agree with you and I say that the answer is letter E.
However, this problem comes form the GMAT Kaplan book and in the answers it actually said that the right answer is letter C.
I read the explainations already but I still do not get it.
What do you think about this ???
Thanks for all the answers and I also agree with you and I say that the answer is letter E.
However, this problem comes form the GMAT Kaplan book and in the answers it actually said that the right answer is letter C.
I read the explainations already but I still do not get it.
What do you think about this ???
parallel_chase wrote:The answer should be E.
Statement I
9x=4y
x=4
y=9
36=36, x<y
x=-4
y=-9
-36 = -36, x>y
SEE the second condition
Hence Insufficient.
Statement II
x>-y
It does not tell us anything about positive y, therefore insufficient.
Hence the answer is E.
It should be C. See second condition
Whats the OA?
I agree with C.
First says, both x and y could be 0, in which case it is a NO. For +ve y, x <y and -ve y, x > y.
Second statement by itself is not sufficient.
Now, from (1), we have x = (4/9) y. From 2, we have (x+y) > 0. Put these together, and you get y>0, in which case x<y.
First says, both x and y could be 0, in which case it is a NO. For +ve y, x <y and -ve y, x > y.
Second statement by itself is not sufficient.
Now, from (1), we have x = (4/9) y. From 2, we have (x+y) > 0. Put these together, and you get y>0, in which case x<y.
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We can all agree that neither statements is sufficient alone, thus it comes down to C or E.
9x = 4y
x > -y
multiple the second equation by 9
9x > -9y
4y > -9y (substitute 9x with 4y according to 1st equation)
y > 0
x > 0 (x = 4/9y and y>0)
if they are both positive, x = 4/9y must be x < y.
C. Hope this helps.
9x = 4y
x > -y
multiple the second equation by 9
9x > -9y
4y > -9y (substitute 9x with 4y according to 1st equation)
y > 0
x > 0 (x = 4/9y and y>0)
if they are both positive, x = 4/9y must be x < y.
C. Hope this helps.