P/S need help...

This topic has expert replies
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Fri Feb 16, 2007 8:33 pm

P/S need help...

by metropia » Mon Mar 26, 2007 2:52 pm
Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?


A. m+4/m(m-4) B. 2m-4/m(m-4) C.4m-4/m(m-4) D. 4m-8/m(m-4)
E. 4m-12/m(m-4)


I tried to plug in the number (assume that m=12) ...can't get the right answer.

User avatar
Community Manager
Posts: 789
Joined: Sun Jan 28, 2007 3:51 pm
Location: Silicon valley, California
Thanked: 30 times
Followed by:1 members

by jayhawk2001 » Mon Mar 26, 2007 7:01 pm
First 3 sandwiches divided amongst m people, so each person gets 3/m
of the sandwich.

Last sandwich divided among m-4. So each person gets 1/(m-4)

So carol eats 3/m + 1/(m-4) = (4m-12) / (m(m-4))

Legendary Member
Posts: 559
Joined: Tue Mar 27, 2007 1:29 am
Thanked: 5 times
Followed by:2 members

by Cybermusings » Wed Mar 28, 2007 6:38 am
Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?


A. m+4/m(m-4)
B. 2m-4/m(m-4)
C.4m-4/m(m-4)
D. 4m-8/m(m-4)
E. 4m-12/m(m-4)


This one seems easy...Lets hope I get it right

First 3 sandwiches divided amongst m students

Thus each student gets 3/m sandwich

Last sandwich divided amongst m - 4 students

Therefore each of those m-4 students gets 1/m-4 sandwich

Carol ate 3/m + 1/m-4 sandwich

= (3(m-4)+m)/m(m-4)

= 3m - 12 + m / m (m - 4)

= 4m - 12 / m (m - 4)

Hence E

Junior | Next Rank: 30 Posts
Posts: 23
Joined: Tue Jun 28, 2016 6:39 am
Thanked: 8 times
Followed by:3 members
GMAT Score:780

by Danny@GMATAcademy » Tue Jul 05, 2016 5:22 pm
Value substitution and algebra both work nicely for this question. See videos below:

Value substitution: https://youtu.be/L-fqOMzmglM

Algebra: https://youtu.be/usxNJ89lAZs

Hope they help.

User avatar
Master | Next Rank: 500 Posts
Posts: 410
Joined: Fri Mar 13, 2015 3:36 am
Location: Worldwide
Thanked: 120 times
Followed by:8 members
GMAT Score:770

by OptimusPrep » Wed Jul 06, 2016 6:59 am
metropia wrote:Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?


A. m+4/m(m-4) B. 2m-4/m(m-4) C.4m-4/m(m-4) D. 4m-8/m(m-4)
E. 4m-12/m(m-4)


I tried to plug in the number (assume that m=12) ...can't get the right answer.
Instead of number substituting, simple algebra would get you the answer quickly

3 sandwiches divided among m students.
Hence each student gets 3/m sandwiches

For the last one, 4 students do not want to eat, hence remaining students = m - 4
Each student gets 1/ (m-4) sandwiches

Total sandwiches eaten by Carol = 3/m + 1/(m-4) = 3m - 12 + m / m(m-4) = 4m-12/m(m-4)

Correct Option: E

GMAT Instructor
Posts: 2630
Joined: Wed Sep 12, 2012 3:32 pm
Location: East Bay all the way
Thanked: 625 times
Followed by:119 members
GMAT Score:780

by Matt@VeritasPrep » Thu Jul 07, 2016 3:42 pm
Since the OP asked the question in 2007, I think we can assume the sandwiches are long spoiled, and there's no need to resurrect the thread.