Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?
A. m+4/m(m-4) B. 2m-4/m(m-4) C.4m-4/m(m-4) D. 4m-8/m(m-4)
E. 4m-12/m(m-4)
I tried to plug in the number (assume that m=12) ...can't get the right answer.
P/S need help...
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- jayhawk2001
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First 3 sandwiches divided amongst m people, so each person gets 3/m
of the sandwich.
Last sandwich divided among m-4. So each person gets 1/(m-4)
So carol eats 3/m + 1/(m-4) = (4m-12) / (m(m-4))
of the sandwich.
Last sandwich divided among m-4. So each person gets 1/(m-4)
So carol eats 3/m + 1/(m-4) = (4m-12) / (m(m-4))
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Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?
A. m+4/m(m-4)
B. 2m-4/m(m-4)
C.4m-4/m(m-4)
D. 4m-8/m(m-4)
E. 4m-12/m(m-4)
This one seems easy...Lets hope I get it right
First 3 sandwiches divided amongst m students
Thus each student gets 3/m sandwich
Last sandwich divided amongst m - 4 students
Therefore each of those m-4 students gets 1/m-4 sandwich
Carol ate 3/m + 1/m-4 sandwich
= (3(m-4)+m)/m(m-4)
= 3m - 12 + m / m (m - 4)
= 4m - 12 / m (m - 4)
Hence E
A. m+4/m(m-4)
B. 2m-4/m(m-4)
C.4m-4/m(m-4)
D. 4m-8/m(m-4)
E. 4m-12/m(m-4)
This one seems easy...Lets hope I get it right
First 3 sandwiches divided amongst m students
Thus each student gets 3/m sandwich
Last sandwich divided amongst m - 4 students
Therefore each of those m-4 students gets 1/m-4 sandwich
Carol ate 3/m + 1/m-4 sandwich
= (3(m-4)+m)/m(m-4)
= 3m - 12 + m / m (m - 4)
= 4m - 12 / m (m - 4)
Hence E
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Value substitution and algebra both work nicely for this question. See videos below:
Value substitution: https://youtu.be/L-fqOMzmglM
Algebra: https://youtu.be/usxNJ89lAZs
Hope they help.
Value substitution: https://youtu.be/L-fqOMzmglM
Algebra: https://youtu.be/usxNJ89lAZs
Hope they help.
Email: [email protected]
- OptimusPrep
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Instead of number substituting, simple algebra would get you the answer quicklymetropia wrote:Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?
A. m+4/m(m-4) B. 2m-4/m(m-4) C.4m-4/m(m-4) D. 4m-8/m(m-4)
E. 4m-12/m(m-4)
I tried to plug in the number (assume that m=12) ...can't get the right answer.
3 sandwiches divided among m students.
Hence each student gets 3/m sandwiches
For the last one, 4 students do not want to eat, hence remaining students = m - 4
Each student gets 1/ (m-4) sandwiches
Total sandwiches eaten by Carol = 3/m + 1/(m-4) = 3m - 12 + m / m(m-4) = 4m-12/m(m-4)
Correct Option: E
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Since the OP asked the question in 2007, I think we can assume the sandwiches are long spoiled, and there's no need to resurrect the thread.