Question: A company plans to assign identification numbers to its employees. Each number is to consist of 4 different digits from 0 to 9, inclusive, except that the 1st digit cannot be 0. How many different identification numbers are possible?
I feel that the answer should be 9x10x10x10=9000.
But I see that the answer is 4536. Can someone explain how?
Thx
Vijay.
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Hi Vijay,vijaynarayanan wrote:Question: A company plans to assign identification numbers to its employees. Each number is to consist of 4 different digits from 0 to 9, inclusive, except that the 1st digit cannot be 0. How many different identification numbers are possible?
I feel that the answer should be 9x10x10x10=9000.
But I see that the answer is 4536. Can someone explain how?
Thx
Vijay.
First place can be filled by 9 digits 1 to 9
second by 9 [because, we cannot repaet the first digit]
third by 8 [cant repeat 1 and 2 digits ]
fourth by 7
so total 9*9*8*7 = 4536
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good questionvijaynarayanan wrote:Question: A company plans to assign identification numbers to its employees. Each number is to consist of 4 different digits from 0 to 9, inclusive, except that the 1st digit cannot be 0. How many different identification numbers are possible?
I feel that the answer should be 9x10x10x10=9000.
if you take
But I see that the answer is 4536. Can someone explain how?
Thx
Vijay.
your reasoning makes sense because we are not talking about non repeatation
as for example 1111 and 2222 are all unique
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