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harsh.champ
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Topic: P & C

Mon Feb 08, 2010 4:02 pm

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How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed?

(A)499
(B)500
(C)375
(D)376
(E)501

The OA is D.
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Mon Feb 08, 2010 7:44 pm

Consider first the numbers we could make which are less than 4000. The first digit can be 1, 2 or 3, so we have three choices for the first digit. For the remaining digits we have 5 choices (repetition is allowed), so we can make 355*5 = 375 such numbers. Since we must also include the number 4000 in our count, there are 375+1 = 376 numbers in total. _________________ private GMAT tutor contact me via the tutor directory at www.gmatix.com

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Mon Feb 08, 2010 10:29 pm

harsh.champ wrote: How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed? (A)499 (B)500 (C)375 (D)376 (E)501 The OA is D. First digit can be 1,2,3 so 3 ways; second digit can be selected in 5 ways ; third in 5 ways, 4 th in 5 ways and 4000 3*5^3+1 = 376 _________________ Always borrow money from a pessimist, he doesn't expect to be paid back.

shashank.ism
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Wed Feb 10, 2010 1:03 pm

harsh.champ wrote: How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed? (A)499 (B)500 (C)375 (D)376 (E)501 The OA is D. 999<I<=4000 digits that can be used 0,1,2,3,4 so total no. of numbers formed 3x5x5x5 +1=376 _________________ http://www.webmaggu.com - Share your favorite interesting links here. http://searchgreener.co.cc - Always search green. Nothing is Impossible, even Impossible says I'm possible.

komal
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Tue Feb 16, 2010 8:44 pm

harsh.champ wrote: How many integers, greater than 999 but not greater than 4000, can be formed with the digits 0, 1, 2, 3 and 4, if repetition of digits is allowed? (A)499 (B)500 (C)375 (D)376 (E)501 The OA is D. The smallest number in the series is 1000, a 4-digit number. The largest number in the series is 4000, the only 4-digit number to start with 4. The left most digit (thousands place) of each of the 4 digit numbers other than 4000 can take one of the 3 values 1 or 2 or 3. The next 3 digits (hundreds, tens and units place) can take any of the 5 values 0 or 1 or 2 or 3 or 4. Hence, there are 3 * 5 * 5 * 5 or 375 numbers from 1000 to 3999. Including 4000, there will be 376 such numbers. _________________ https://www.e-gmat.com/