OG 13 #178 - Virtual Reality

This topic has expert replies
Legendary Member
Posts: 641
Joined: Tue Feb 14, 2012 3:52 pm
Thanked: 11 times
Followed by:8 members

by gmattesttaker2 » Mon Apr 22, 2013 5:48 pm
Param800 wrote:Image

Let me try to explain you why we are subtracting 2 * ( ABC )

So, our formula is this--

TOTAL = A + B + C - ( Sum of EXACTLY 2 group overlap)- 2*( all three) + Neither

Notice that EXACTLY (only) 2-group overlaps is not the same as 2-group overlaps:
Elements which are common only for A and B are in section d (so elements which are common ONLY for A and B refer to the elements which are in A and B but not in C);
Elements which are common only for A and C are in section e;
Elements which are common only for B and C are in section f.

Let's see how this formula is derived. Again: when we add three groups A, B, and C some sections are counted more than once. For instance: sections d, e, and f are counted twice and section g thrice. Hence we need to subtract sections d, e, and f ONCE (to count section g only once) and subtract section g TWICE (again to count section g only once).

When we subtract Sum of EXACTLY 2 group overlap from A + B + C we subtract sections d,e,and f once ( fine) and next we need to subtract ONLY section g TWICE.

For 3 set probability questions, I have developed ( or gathered ) these three basic formulas and I am able to solve any tough problem with it.

FIRST FORMULA -

TOTAL = A + B + C - ( Sum of 2 group overlap) + ( All three ) + Neither

SECOND FORMULA -

TOTAL = A + B + C - ( Sum of EXACTLY 2 group overlap)- 2*( all three) + Neither

THIRD FORMULA-

TOTAL = ( Exactly one group ) + ( Exactly 2 groups) + ( All three ) + Neither

I hope this clarifies your doubt :)


Hello,

I used the same Venn diagram from Param800. Also, my approach is similar to one of the posts answered by rijul007.

https://www.beatthegmat.com/ps-virtual-r ... 09926.html

My approach was as follows:

120 = a + d + e + g
90 = b + d + f + g
225 = c + e + f + g

So, 435 = a + b + c + 2d + 2e + 2f + 3g
= a + b + c + 2(d + e + f) + 3g - Eq. 1

Since 35% experienced at least 2 of these effects,

105 = d + e + f - Eq. 2

Substituting Eq.2 in Eq. 1:
435 = a + b + c + 2(105) + 3g

So, 225 = a + b + c + 3g - Eq. 3

Since 300 subjects participated in the experiment,

300 = a + b + c + d + e + f + g

So, 300 = a + b + c + 105 + g (from Eq. 2)

So, 195 = a + b + c + g - Eq. 4

Substituting Eq. 4 in Eq. 3,

225 = a + b + c + g + 2g
= 195 + 2g
2g = 30
g = 15

Substituting g = 15 in Eq. 4,

195 = a + b + c + 15

So, a + b + c = 180

I was wondering if this approach is correct?

I was confused was the question says 35% experienced exactly 2 of these effects. Hence I take:

105 = d + e + f (where 105 = 35% of 300)

Is this correct? I was first thinking that it should be 105 = d, 105 = e, 105 = f but then got a feeling that this would be incorrect. I think this is similar to what the question is asking i.e. how many of the subject experienced only one of these effects? i.e. how many experienced a or b or c?
Is this understanding correct? Thanks.


Best Regards,
Sri

User avatar
GMAT Instructor
Posts: 1052
Joined: Fri May 21, 2010 1:30 am
Thanked: 335 times
Followed by:98 members

by Patrick_GMATFix » Tue Jan 28, 2014 8:55 am
The illustrated solution below is taken from the GMATFix App.

Image

-Patrick
  • Ask me about tutoring.

Junior | Next Rank: 30 Posts
Posts: 25
Joined: Wed Mar 04, 2015 5:16 pm
Location: India
Thanked: 1 times

by Priyaranjan » Thu Mar 26, 2015 4:32 pm
Thanks Sir, the answer is very simple as compared to the one in the OG.
GMATGuruNY wrote:
wied81 wrote:178. Of the 300 subjects who participated in an experiment using virtual-reality therapy to reduce their fear of heights, 40 percent experienced sweaty palms, 30 percent experienced vomiting, and 75 percent experienced dizziness. If all of the subjects experienced at least one of these effects and 35 percent of the subjects experienced exactly two of these effects, how many of the subjects experienced only one of these effects?

A) 105

B) 125

C) 130

D) 180

E) 195

OA: D

I know that for 'both, neither' PS questions containing two variables it is nice to use the 'Group A + Group B + Neither - Both = Total' formula but for PS questions containing three variables, as this one does, is there a similar formula? These questions take up a big chunk of time, for me personally, and it would be nice to be able to plug in a formula if applicable.

Thanks in advance for any guidance.
Here is the formula for 3 overlapping groups:

T = A + B + C - (AB + AC + BC) - 2(ABC)

The big idea with overlapping group problems is to SUBTRACT THE OVERLAPS.
When we add together everyone in A, everyone in B, and everyone in C:
Those in exactly 2 of the groups (AB+AC+BC) are counted twice, so they need to be subtracted from the total ONCE.
Those in all 3 groups (ABC) are counted 3 times, so they need to be subtracted from the total TWICE.
By subtracting the overlaps, we ensure that no one is overcounted.

In the problem above:
Let T = 100%.
Sweaty palms = 40.
Vomiting = 30.
Dizziness = 75.
Exactly 2 of the groups = 35.
Let x = the percentage in all 3 groups.

Plugging these values into the formula, we get:
100 = 40 + 30 + 75 - 35 - 2x
100 = 110 - 2x
x=5.

Since 35% are in 2 of the groups and 5% are in all 3 groups, the percentage in exactly one of the groups = 100-35-5 = 60.
Number in exactly one of the groups = .6(300) = 180.

The correct answer is D.

Newbie | Next Rank: 10 Posts
Posts: 7
Joined: Thu Jan 07, 2016 9:15 pm

by HAmjad » Sat Jan 30, 2016 12:15 am
GMATGuruNY wrote:
wied81 wrote:178. Of the 300 subjects who participated in an experiment using virtual-reality therapy to reduce their fear of heights, 40 percent experienced sweaty palms, 30 percent experienced vomiting, and 75 percent experienced dizziness. If all of the subjects experienced at least one of these effects and 35 percent of the subjects experienced exactly two of these effects, how many of the subjects experienced only one of these effects?

A) 105

B) 125

C) 130

D) 180

E) 195

OA: D

I know that for 'both, neither' PS questions containing two variables it is nice to use the 'Group A + Group B + Neither - Both = Total' formula but for PS questions containing three variables, as this one does, is there a similar formula? These questions take up a big chunk of time, for me personally, and it would be nice to be able to plug in a formula if applicable.

Thanks in advance for any guidance.
Here is a useful formula for 3 overlapping groups:

T = A + B + C - (AB + AC + BC) - 2(ABC)

The big idea with overlapping group problems is to SUBTRACT THE OVERLAPS.
When we add together everyone in A, everyone in B, and everyone in C:
Those in exactly 2 of the groups (AB+AC+BC) are counted twice, so they need to be subtracted from the total ONCE.
Those in all 3 groups (ABC) are counted 3 times, so they need to be subtracted from the total TWICE.
By subtracting the overlaps, we ensure that no one is overcounted.

In the problem above:
Let T = 100%.
Sweaty palms = 40.
Vomiting = 30.
Dizziness = 75.
Exactly 2 of the groups = 35.
Let x = the percentage in all 3 groups.

Plugging these values into the formula, we get:
100 = 40 + 30 + 75 - 35 - 2x
100 = 110 - 2x
x=5.

Since 35% are in 2 of the groups and 5% are in all 3 groups, the percentage in exactly one of the groups = 100-35-5 = 60.
Number in exactly one of the groups = .6(300) = 180.

The correct answer is D.


I used the same formula t=a+b+c-(in all 2)-2(in all 3)

I found out the values
a=120
b=90
c=225
in all 2= 105

300=120+90+225-105-2(in all 3)
in all 3=30/2
in all 3=15

then

a+b+c=300-135
a+b+c=175

How am I doing it wrong? Please help

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Sat Jan 30, 2016 4:14 am
HAmjad wrote: I used the same formula t=a+b+c-(in all 2)-2(in all 3)

I found out the values
a=120
b=90
c=225
in all 2= 105

300=120+90+225-105-2(in all 3)
in all 3=30/2
in all 3=15

then

a+b+c=300-135
a+b+c=175

How am I doing it wrong? Please help
The value in red is incorrect.

The prompt indicates the following:
Total = 300.
Number in exactly 2 groups = 105.

You calculated the following:
Number in all 3 groups = 15.

Thus:
Number in exactly 1 group = total - (exactly 2) - (all 3) = 300 - 105 - 15 = 180.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

Newbie | Next Rank: 10 Posts
Posts: 7
Joined: Thu Jan 07, 2016 9:15 pm

by HAmjad » Sat Jan 30, 2016 8:59 pm
GMATGuruNY wrote:
HAmjad wrote: I used the same formula t=a+b+c-(in all 2)-2(in all 3)

I found out the values
a=120
b=90
c=225
in all 2= 105

300=120+90+225-105-2(in all 3)
in all 3=30/2
in all 3=15

then

a+b+c=300-135
a+b+c=175

How am I doing it wrong? Please help
The value in red is incorrect.

The prompt indicates the following:
Total = 300.
Number in exactly 2 groups = 105.

You calculated the following:
Number in all 3 groups = 15.

Thus:
Number in exactly 1 group = total - (exactly 2) - (all 3) = 300 - 105 - 15 = 180.

But this the the formula:
T = A + B + C - (AB + AC + BC) - 2(ABC)

Why aren't we multiplying 15 by 2 in this? Is this formula only used to calculate the unknown values and then we have to solve the questions intuitively?

Junior | Next Rank: 30 Posts
Posts: 18
Joined: Fri Nov 10, 2017 9:01 am

by kamalj » Sun Nov 26, 2017 7:42 am
In the problem above:
Let T = 100%.
Sweaty palms = 40.
Vomiting = 30.
Dizziness = 75.
Exactly 2 of the groups = 35.
Let x = the percentage in all 3 groups.

Plugging these values into the formula, we get:
100 = 40 + 30 + 75 - 35 - 2x
100 = 110 - 2x
x=5.
Hi GMATGuruNY ,

Just a quick question.

Why did we select 100 when 300 is given?

Please explain.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 7261
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

by Scott@TargetTestPrep » Mon Oct 07, 2019 10:20 am
wied81 wrote:178. Of the 300 subjects who participated in an experiment using virtual-reality therapy to reduce their fear of heights, 40 percent experienced sweaty palms, 30 percent experienced vomiting, and 75 percent experienced dizziness. If all of the subjects experienced at least one of these effects and 35 percent of the subjects experienced exactly two of these effects, how many of the subjects experienced only one of these effects?

A) 105

B) 125

C) 130

D) 180

E) 195

OA: D
This is a 3-circle Venn Diagram problem. Because we do not know the number of unique items in this particular set, we can use the following formula:

Total # of Unique Elements = # in (Group A) + # in (Group B) + # in (Group C) - # in (Groups of Exactly Two) - 2 [#in (Group of Exactly Three)] + # in (Neither)

Next we can label our groups with the information presented.

# in Group A = # who experienced sweaty palms

# in Group B = # who experienced vomiting

# in Group C = # who experienced dizziness

We are given that, of the 300 subjects who participated in an experiment using virtual-reality therapy to reduce their fear of heights, 40 percent experienced sweaty palms, 30 percent experienced vomiting, and 75 percent experienced dizziness.

We can solve for the number in each group:

# who experienced sweaty palms = 300 x 0.4 = 120

# who experienced vomiting = 300 x 0.3 = 90

# who experienced dizziness = 300 x 0.75 = 225

We are also given that all of the subjects experienced at least one of these effects and 35 percent of the subjects experienced exactly two of these effects.

This means the following:

# in Groups of Exactly Two = 300 x 0.35 = 105

Since all the subjects experienced at least one of the effects, it means that the # in (Neither) is equal to zero. We can now plug in all the information we have into our formula, in which T represents # in (Group of Exactly Three).

Total # of Unique Elements = # in (Group A) + # in (Group B) + # in (Group C) - # in (Groups of Exactly Two) - 2 [# in (Group of Exactly Three)] + # in (Neither)

300 = 120 + 90 + 225 - 105 - 2T + 0

300 = 330 - 2T

30 = 2T

15 = T

Now that we have determined a value for T, we are very close to finishing the problem. The question asks how many of the subjects experienced only one of these effects.

To determine this, we can set up one final formula.

Total = # who experienced only 1 effect + # who experienced two effects + # who experienced all 3 effects + # who experienced no effects

We can let x represent the # who experienced only 1 effect.

300 = x + 105 + 15 + 0

300 = x + 120

180 = x

Alternate Solution:

Alternatively, we can use the following formula for percentages:

100= % of (Group A) + % of (Group B) + % of (Group C) - % of (Groups of Exactly Two) - 2 [% of (Group of Exactly Three)] + % of (Neither)

Next we can label our groups with the information presented.

% of Group A = % who experienced sweaty palms

% of Group B = % who experienced vomiting

% of Group C = % who experienced dizziness

Thus, we have:

100 = 40 + 30 + 75 - 35 - 2[% of (Group of Exactly Three)] + 0

100 = 110 - 2[% of (Group of Exactly Three)]

2[% of (Group of Exactly Three)] = 10

% of (Group of Exactly Three) = 5

Notice that we have:

100 = % of (Group of Exactly One) + % of (Group of Exactly Two) + % of (Group of All Three)

100 = % of (Group of Exactly One) + 35 + 5 + 0

100 = % of (Group of Exactly One) + 40

% of (Group of Exactly One) = 60

Thus, there are 300 * 0.6 = 180 people belonging to exactly one of the groups.

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage