If 1 < x < y < z, which of the following has the greatest value?
A) z(x+1)
B) z(y+1)
C) x(y+z)
D) y(x+z)
E) z(x+y)
E
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OG 1 < x < y < z
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AbeNeedsAnswers
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Hi AbeNeedsAnswers,
We're told that 1 < X < Y < Z. We're asked which of the answers has the GREATEST value. This question can be solved by TESTing VALUES.
IF...
X = 2, Y = 3, Z = 4
Answer A: 4(3) = 12
Answer B: 4(4) = 16
Answer C: 2(7) = 14
Answer D: 3(6) = 18
Answer E: 4(5) = 20
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
We're told that 1 < X < Y < Z. We're asked which of the answers has the GREATEST value. This question can be solved by TESTing VALUES.
IF...
X = 2, Y = 3, Z = 4
Answer A: 4(3) = 12
Answer B: 4(4) = 16
Answer C: 2(7) = 14
Answer D: 3(6) = 18
Answer E: 4(5) = 20
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
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Matt@VeritasPrep
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We could also do algebra. Here's how to compare D vs E, and from this you can extrapolate how to do the others:
y * (x + z) vs z * (x + y)
yx + yz vs xz + yz
subtract yz from both sides:
yx vs xz
divide both sides by x:
y vs z
z is bigger, so the right side is bigger, so E > D.
y * (x + z) vs z * (x + y)
yx + yz vs xz + yz
subtract yz from both sides:
yx vs xz
divide both sides by x:
y vs z
z is bigger, so the right side is bigger, so E > D.
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Jeff@TargetTestPrep
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We can let x = 2, y = 3, and z = 4, and we have:AbeNeedsAnswers wrote:If 1 < x < y < z, which of the following has the greatest value?
A) z(x+1)
B) z(y+1)
C) x(y+z)
D) y(x+z)
E) z(x+y)
E
A) z(x+1)
4(3) = 12
B) z(y+1)
4(4) = 16
C) x(y+z)
2(7) = 14
D) y(x+z)
3(6) = 18
E) z(x+y)
4(5) = 20
Answer: E
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[1] Assign Test Values
Must follow rule: 1 < x < y < y
x = 2
y = 3
z = 4
[2] Plug In & Calculate
A. z(x + 1) -> 4(2 + 1) = 12
B. z(y + 1) -> 4( 3 + 1) = 16
C. x(y + z) -> 2(3 + 4) = 14
D. y(x + z) -> 3(2 + 4) = 18
E. z(x + y) -> 4(2 + 3) = 20
Answer: E
Must follow rule: 1 < x < y < y
x = 2
y = 3
z = 4
[2] Plug In & Calculate
A. z(x + 1) -> 4(2 + 1) = 12
B. z(y + 1) -> 4( 3 + 1) = 16
C. x(y + z) -> 2(3 + 4) = 14
D. y(x + z) -> 3(2 + 4) = 18
E. z(x + y) -> 4(2 + 3) = 20
Answer: E
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Bijaya Krushna Mohapatra
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x=2,y=3,z=4 , which satisfies the condition 1<x<y<z
If we use this values in the answer options
A. z(x + 1) = 4(3) = 12
B. z(y + 1) = 4(4) = 16
C. x(y + z) = 2(7) = 14
D. y(x + z) = 3(6) = 18
E. z(x + y) = 4(5) = 20 So max value we are getting is E.
If we use this values in the answer options
A. z(x + 1) = 4(3) = 12
B. z(y + 1) = 4(4) = 16
C. x(y + z) = 2(7) = 14
D. y(x + z) = 3(6) = 18
E. z(x + y) = 4(5) = 20 So max value we are getting is E.
