Need help with negative inequality

ildude02

If x is an integer, what's the value of X?

1)1/5 < 1/(x+1) < 1/2
2)(x-3)(x-4) = 0;

I have solved this question to find the answer, but I have a question with regards to how I solved statement 1 and wanted to hear your thoughts.

For statement 1, (x+1) can either be positve or negative, so if (x+1) is postive, we dont need to worry abt the reversing the inequalities, so we get, 1 < x < 4;

When we consider (x+1) being negative, this is where I wanted to get your input;

Can we just substitue (x+1) with -(x+1) and try to solve the inequality? as in; 1/5 < 1/-(x+1) < 1/2 . Is that OK? Or, do we need to reverse the inequality and leave the (x+1) as in; 1/5 > 1/(x+1) > 1/2; Solving both the possibilites obviously give different values.

wilderness · Posted: Tue Jul 08, 2008 3:45 am Post subject:

Hi,

I think we do not need to take -ve into consideration for (1) because it says 1/(x+1) is between 1/5 and 1/2 i.e 1/(x+1) is between 0.2 and 0.5. So its not negative.

IMHO the best way to solve 1 is just invert the equations and change the signs (Is there any rule that forbids us from doing so ?? )
Then we have simply 5 > (x+1) > 2
hence 4 > x > 1

The answer is C.

Ian Stewart · Posted: Tue Jul 08, 2008 6:23 am Post subject:

wilderness · Posted: Tue Jul 08, 2008 7:30 am Post subject:

Thanks. You just keep amazing me with your tips.

ildude02 · Posted: Tue Jul 08, 2008 8:11 am Post subject:

I missed it, you are gith that we dont need to consider (x+1) < 0 since it will not satify the given inequality. Thanks.

But my main question was, if we do need to consider one, can we just substitue the variable x+1 with -(x+1) and continue solving the inequality to find the upper an dtjhe lower limit? Appreciate your response.

AleksandrM · Posted: Tue Jul 08, 2008 10:32 am Post subject:

Hey, I ended up with:

1) 10/(x + 1) - 5 < 0

2) x = 3 x = 4

Both: If x = 4, then 1) does not hold true. If x = 3, then 1 holds true.

And so I went with C.

Is my approach correct?

jay2007 · Posted: Tue Jul 08, 2008 10:36 am Post subject:

Solving the first in equality i get the values of x as 3 or 4

1/5 < 1/(x+1) means, x=1,2,3,4,0
1/(x+1) < 1/2 means, x=3,4,5,..... or -2, -3, -4....

So, x should be 3 or 4

Solving the second equation i get the values of x as 3 or 4.

So, my answer is E.

What is the OA?

AleksandrM · Posted: Tue Jul 08, 2008 10:50 am Post subject:

jay,

For the first one, you cannot cross-multiply because you do not know the sign of x, therefore you do not know whether to "flip" the inequality sign or not.

zakir · Posted: Tue Jul 08, 2008 10:15 pm Post subject:

I would do this as-
From 1st equation:
(x+1)<5, so x <4>2, so x>1
x can be either 2 or 3

From 2nd equation:
x=3, or x=4

Combining 1st and 2nd, x=3.

So the correct answer is C.

(x is not negative, as that would make 1st equation untrue)

lunarpower · Posted: Thu Jul 10, 2008 11:48 pm Post subject: