If x is an integer, what's the value of X?
1)1/5 < 1/(x+1) < 1/2
2)(x-3)(x-4) = 0;
I have solved this question to find the answer, but I have a question with regards to how I solved statement 1 and wanted to hear your thoughts.
For statement 1, (x+1) can either be positve or negative, so if (x+1) is postive, we dont need to worry abt the reversing the inequalities, so we get, 1 < x < 4;
When we consider (x+1) being negative, this is where I wanted to get your input;
Can we just substitue (x+1) with -(x+1) and try to solve the inequality? as in; 1/5 < 1/-(x+1) < 1/2 . Is that OK? Or, do we need to reverse the inequality and leave the (x+1) as in; 1/5 > 1/(x+1) > 1/2; Solving both the possibilites obviously give different values.
Need help with negative inequality
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 102
- Joined: Sat Mar 15, 2008 4:03 am
- Thanked: 4 times
Hi,
I think we do not need to take -ve into consideration for (1) because it says 1/(x+1) is between 1/5 and 1/2 i.e 1/(x+1) is between 0.2 and 0.5. So its not negative.
IMHO the best way to solve 1 is just invert the equations and change the signs (Is there any rule that forbids us from doing so ?? )
Then we have simply 5 > (x+1) > 2
hence 4 > x > 1
The answer is C.
I think we do not need to take -ve into consideration for (1) because it says 1/(x+1) is between 1/5 and 1/2 i.e 1/(x+1) is between 0.2 and 0.5. So its not negative.
IMHO the best way to solve 1 is just invert the equations and change the signs (Is there any rule that forbids us from doing so ?? )
Then we have simply 5 > (x+1) > 2
hence 4 > x > 1
The answer is C.
GMAT/MBA Expert
- Ian Stewart
- GMAT Instructor
- Posts: 2621
- Joined: Mon Jun 02, 2008 3:17 am
- Location: Montreal
- Thanked: 1090 times
- Followed by:355 members
- GMAT Score:780
You can certainly do this if you know everything is positive. If x and y are positive, and you have the inequality:wilderness wrote: IMHO the best way to solve 1 is just invert the equations and change the signs (Is there any rule that forbids us from doing so ?? ) .
1/x < 1/y
then you can multiply both sides by xy to get:
y < x
We don't need to worry about whether to reverse the inequality, provided we know that x and y are both positive. The same is true if x and y are both negative: then xy is positive, so we can multiply by xy without reversing the inequality. You do need to be careful, however, when x and y have opposite signs. Then, when you multiply by xy, you are multiplying by a negative, and you must reverse the inequality. If, say:
1/x < 1/y
then x could be negative, and y positive, and we have, multiplying by xy and reversing the inequality:
y > x
So yes, there is a rule one can follow here- but you need to be very careful if you don't know the signs of x and y.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com
ianstewartgmat.com
ianstewartgmat.com
-
- Master | Next Rank: 500 Posts
- Posts: 102
- Joined: Sat Mar 15, 2008 4:03 am
- Thanked: 4 times
-
- Master | Next Rank: 500 Posts
- Posts: 320
- Joined: Sun Jan 13, 2008 10:00 pm
- Thanked: 10 times
I missed it, you are gith that we dont need to consider (x+1) < 0 since it will not satify the given inequality. Thanks.
But my main question was, if we do need to consider one, can we just substitue the variable x+1 with -(x+1) and continue solving the inequality to find the upper an dtjhe lower limit? Appreciate your response.
But my main question was, if we do need to consider one, can we just substitue the variable x+1 with -(x+1) and continue solving the inequality to find the upper an dtjhe lower limit? Appreciate your response.
wilderness wrote:Hi,
I think we do not need to take -ve into consideration for (1) because it says 1/(x+1) is between 1/5 and 1/2 i.e 1/(x+1) is between 0.2 and 0.5. So its not negative.
IMHO the best way to solve 1 is just invert the equations and change the signs (Is there any rule that forbids us from doing so ?? )
Then we have simply 5 > (x+1) > 2
hence 4 > x > 1
The answer is C.
- AleksandrM
- Legendary Member
- Posts: 566
- Joined: Fri Jan 04, 2008 11:01 am
- Location: Philadelphia
- Thanked: 31 times
- GMAT Score:640
Hey, I ended up with:
1) 10/(x + 1) - 5 < 0
2) x = 3 x = 4
Both: If x = 4, then 1) does not hold true. If x = 3, then 1 holds true.
And so I went with C.
Is my approach correct?
1) 10/(x + 1) - 5 < 0
2) x = 3 x = 4
Both: If x = 4, then 1) does not hold true. If x = 3, then 1 holds true.
And so I went with C.
Is my approach correct?
Solving the first in equality i get the values of x as 3 or 4
1/5 < 1/(x+1) means, x=1,2,3,4,0
1/(x+1) < 1/2 means, x=3,4,5,..... or -2, -3, -4....
So, x should be 3 or 4
Solving the second equation i get the values of x as 3 or 4.
So, my answer is E.
What is the OA?
1/5 < 1/(x+1) means, x=1,2,3,4,0
1/(x+1) < 1/2 means, x=3,4,5,..... or -2, -3, -4....
So, x should be 3 or 4
Solving the second equation i get the values of x as 3 or 4.
So, my answer is E.
What is the OA?
- AleksandrM
- Legendary Member
- Posts: 566
- Joined: Fri Jan 04, 2008 11:01 am
- Location: Philadelphia
- Thanked: 31 times
- GMAT Score:640
jay,
For the first one, you cannot cross-multiply because you do not know the sign of x, therefore you do not know whether to "flip" the inequality sign or not.
For the first one, you cannot cross-multiply because you do not know the sign of x, therefore you do not know whether to "flip" the inequality sign or not.
I would do this as-
From 1st equation:
(x+1)<5, so x <4>2, so x>1
x can be either 2 or 3
From 2nd equation:
x=3, or x=4
Combining 1st and 2nd, x=3.
So the correct answer is C.
(x is not negative, as that would make 1st equation untrue)
From 1st equation:
(x+1)<5, so x <4>2, so x>1
x can be either 2 or 3
From 2nd equation:
x=3, or x=4
Combining 1st and 2nd, x=3.
So the correct answer is C.
(x is not negative, as that would make 1st equation untrue)
GMAT/MBA Expert
- lunarpower
- GMAT Instructor
- Posts: 3380
- Joined: Mon Mar 03, 2008 1:20 am
- Thanked: 2256 times
- Followed by:1535 members
- GMAT Score:800
nope; you left off the left side of the double inequality in statement 1. your version (10/(x+1) - 5 < 0) is a rearrangement of 1/(x+1) < 1/2; you've completely neglected the fact that, per the original problem statement, 1/(x+1) is also greater than 1/5.AleksandrM wrote:Hey, I ended up with:
1) 10/(x + 1) - 5 < 0
2) x = 3 x = 4
Both: If x = 4, then 1) does not hold true. If x = 3, then 1 holds true.
And so I went with C.
Is my approach correct?
this observation totally changes the game, because a number that's stuck between 1/5 and 1/2 must be positive; with just the listed half of the inequality, you can't determine whether 1/(x+1) is positive or negative.
because everything in the double inequality is positive, you can just go ahead and take reciprocals of everything. (RULE: if everything is positive or everything is negative, you can take reciprocals of everything and flip all the inequality signs around.)
this yields 5 > x+1 > 2, or, more traditionally, 2 < x+1 < 5.
therefore, 1 < x < 4.
your rephrase of (2) is correct.
therefore, the answer is still c, although not quite for the reasons you've listed.
Ron has been teaching various standardized tests for 20 years.
--
Pueden hacerle preguntas a Ron en castellano
Potete chiedere domande a Ron in italiano
On peut poser des questions à Ron en français
Voit esittää kysymyksiä Ron:lle myös suomeksi
--
Quand on se sent bien dans un vêtement, tout peut arriver. Un bon vêtement, c'est un passeport pour le bonheur.
Yves Saint-Laurent
--
Learn more about ron
--
Pueden hacerle preguntas a Ron en castellano
Potete chiedere domande a Ron in italiano
On peut poser des questions à Ron en français
Voit esittää kysymyksiä Ron:lle myös suomeksi
--
Quand on se sent bien dans un vêtement, tout peut arriver. Un bon vêtement, c'est un passeport pour le bonheur.
Yves Saint-Laurent
--
Learn more about ron