Data Sufficiency

If x, y and z are positive integers, is xz even?

1) xy is even

2) yz is even

how did you conclude C....both conditions together are not sufficiant for the response.

xy is even =>both x and y even (or) x even and y odd (or)x odd y even
yz is even =>both y and z even (or) y even and z odd (or)y odd z even

if you take the case that
i)(x odd and y even) and (y even and z odd ) = xz is odd
ii)for anyother case xz is even.

so you cant really conclude using both the statements together.

Ahh, I think I mislead the question "xyz" are even... oops

if that is the case than i think the answer is C

IMO - D

E x E = E

E x O = E

So, If xy is even, then (xy).z is even irrespective of z being even or odd

Similarly if yz is even, the (yz).x is even irrespective of x being even or odd.

imo e