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jayhawk2001
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 Posted: Sun May 13, 2007 3:51 pm Post subject: MGMAT - abs problem |
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OA coming after few reply
What is the value of y?
(1) 3|x^2 – 4| = y – 2
(2) |3 – y| = 11 |
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mendiratta
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| Posted: Mon May 14, 2007 12:23 am Post subject: |
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1. Itself can't answer because we don't know x.
2. y=14 or -8 , so insufficient.
but from 1, we get y = 3|x^2 - 4 | + 2
which means 3 * (something positive) + 2, is positive.
So y = 14.
is it C? |
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gabriel
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| Posted: Mon May 14, 2007 12:23 pm Post subject: |
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| ...C for me too ... |
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isisalaska
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| Posted: Mon May 14, 2007 12:31 pm Post subject: |
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E perhpas...if y could be -8 or 14, how can you find out what is the value of "y" in you plug it in statement 1?
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jayhawk2001
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| Posted: Mon May 14, 2007 7:58 pm Post subject: |
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| isisalaska wrote: | | E perhpas...if y could be -8 or 14, how can you find out what is the value of "y" in you plug it in statement 1? |
OA is C.
Isis, using (1), you can see that y is positive (please see mendiratta's
post). So, using 1 and 2, we can converge on y = 14. |
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