Is x > y?
(1) x2 > y
(2) x – |y| > 0
OA B
This one got to me.
- pradeep[/spoiler]
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Ans:B
(1) x^2 > y ( hope x2 in question means x^2)
If x is positive: 25(=x^2)>(=y)4 ==>5>4 AND 9(=x^2)>4(=y)=> 3<4
but if x is negative -5<4 & -3<4 similarly we can check taking y negative(=-4) ..... insufficient as few cases give us x>y and other give us x<y
(2) x – |y| > 0 ==> x>lyl since mod gives positive value this means x is positive and greater than y no matter y is positive or negative
5>l4l==>5>4 OR 5>l-4l ==> 5>-4 ........sufficient
(1) x^2 > y ( hope x2 in question means x^2)
If x is positive: 25(=x^2)>(=y)4 ==>5>4 AND 9(=x^2)>4(=y)=> 3<4
but if x is negative -5<4 & -3<4 similarly we can check taking y negative(=-4) ..... insufficient as few cases give us x>y and other give us x<y
(2) x – |y| > 0 ==> x>lyl since mod gives positive value this means x is positive and greater than y no matter y is positive or negative
5>l4l==>5>4 OR 5>l-4l ==> 5>-4 ........sufficient
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Stmt I
x=-2 y=2 x^2>y but x<y
x=1000 y=1 x^2>y and x>y
INSUFF
Stmt I
x- |y| >0
x>|y|
Case 1: y is positive
By definition of mod function |y|= y if y is 0 or positive we get x>y
Case 2: y is negative
By definition of mod function |y|= -y if y is negative (which makes |something| always positive or 0
Therefore again x>y
SUFF
Choose B
x=-2 y=2 x^2>y but x<y
x=1000 y=1 x^2>y and x>y
INSUFF
Stmt I
x- |y| >0
x>|y|
Case 1: y is positive
By definition of mod function |y|= y if y is 0 or positive we get x>y
Case 2: y is negative
By definition of mod function |y|= -y if y is negative (which makes |something| always positive or 0
Therefore again x>y
SUFF
Choose B
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500 -550 level question
GMATPowerPrep Test1= 740
GMATPowerPrep Test2= 760
Kaplan Diagnostic Test= 700
Kaplan Test1=600
Kalplan Test2=670
Kalplan Test3=570
GMATPowerPrep Test2= 760
Kaplan Diagnostic Test= 700
Kaplan Test1=600
Kalplan Test2=670
Kalplan Test3=570
Ans B.
1. X2>y .. In this case x can either be greater than y (x = 4 and y =1) or
x<y (x = 2, y=3 or x=-2 y=3). Insufficient
2. x-|y| >0
x> |y|
So for any values of y (either positive or negative ) x is greater than y. Sufficient
1. X2>y .. In this case x can either be greater than y (x = 4 and y =1) or
x<y (x = 2, y=3 or x=-2 y=3). Insufficient
2. x-|y| >0
x> |y|
So for any values of y (either positive or negative ) x is greater than y. Sufficient
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A simple one - but I got screwed never the less .. the modulus got me. I was like x > y when y > 0 and x > -(-y) when y < 0 .. so .. lesson learned
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Yes it was. Do you need the screen shot as a proof
In the land of night, the chariot of the sun is drawn by the grateful dead
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