There are 100 employees in a company. Is the salary range greater than $1,000,000?
(1) The range to the median is less than $400,000.
(2) The standard deviation is $200,000
OA l8r ....do explain your logic!!!
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mean & Sd
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abhinav85
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IMO D.
From 1st We get, if i understood it correctly that the range to the median, the range until the median. Being median the maximum value and 1st vale the minumum i.e $400,000. So that means the maximum value will be less then $800,000.Sufficient
From 2nd we get, SD is $200,000.that means every value is $200,000 apart.Sufficient.
From 1st We get, if i understood it correctly that the range to the median, the range until the median. Being median the maximum value and 1st vale the minumum i.e $400,000. So that means the maximum value will be less then $800,000.Sufficient
From 2nd we get, SD is $200,000.that means every value is $200,000 apart.Sufficient.
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geet
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OA is D only...can you give me a detail explanation ,,,,,i m not very good in mean and median partabhinav85 wrote:IMO D.
From 1st We get, if i understood it correctly that the range to the median, the range until the median. Being median the maximum value and 1st vale the minumum i.e $400,000. So that means the maximum value will be less then $800,000.Sufficient
From 2nd we get, SD is $200,000.that means every value is $200,000 apart.Sufficient.
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abhinav85
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[spoiler]
OA is D only...can you give me a detail explanation ,,,,,i m not very good in mean and median part
[/spoiler]
(1) The range to the median is less than $400,000.
Range=Maximum value - minimum value of a set of data.
here we don't the values in the set. And we don't need to know the
values in the set.We just have to make sure that the range of the data
is greater than >$1,000,000.
From the 1st statement we can conclude that the range until the mean is
<$400,000.
So that means Maximum value is $400,000 and mimimum say x.
the range will $400,000 - x= $400,000.
And the median is the value in the middle.
the maximum value of the whole set is <$800,000.
hence sufficient.
From 2nd statement
(2) The standard deviation is $200,000 .
Standard deviation means the deviation from one value to the next value.
e.g 2,4,6,8. Here the SD is 2.
So according to the 2nd statement the standard deviation is $200,000.
Hence D.
Hope it helps.............
OA is D only...can you give me a detail explanation ,,,,,i m not very good in mean and median part
[/spoiler]
(1) The range to the median is less than $400,000.
Range=Maximum value - minimum value of a set of data.
here we don't the values in the set. And we don't need to know the
values in the set.We just have to make sure that the range of the data
is greater than >$1,000,000.
From the 1st statement we can conclude that the range until the mean is
<$400,000.
So that means Maximum value is $400,000 and mimimum say x.
the range will $400,000 - x= $400,000.
And the median is the value in the middle.
the maximum value of the whole set is <$800,000.
hence sufficient.
From 2nd statement
(2) The standard deviation is $200,000 .
Standard deviation means the deviation from one value to the next value.
e.g 2,4,6,8. Here the SD is 2.
So according to the 2nd statement the standard deviation is $200,000.
Hence D.
Hope it helps.............
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adityanarula
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geet
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Median is the middle value but not the average for say median of 1,2,3 is 2abhinav85 wrote:
From the 1st statement we can conclude that the range until the mean is
<$400,000.
So that means Maximum value is $400,000 and mimimum say x.
the range will $400,000 - x= $400,000.
And the median is the value in the middle.
the maximum value of the whole set is <$800,000.
hence sufficient.
.
But median of 1,2,2 is also 2 and median of 1,2,8 is also 2
Now coming on 1 ) here median value is less then or equal to 400,000 but that doest not signify that mx value is less then 800000 it can me more then it.
plz clear my doubt
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Ian Stewart
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This question doesn't make any sense. The 'range to the median' is meaningless; the range from what to the median? The least value in the set? The largest value in the set? There's no way to decide if this is sufficient, since there's no way to know what it means. At a guess, I'd suppose they're trying to say that no value is more than $400,000 from the median, in which case the range can't be greater than $800,000, but you'd never see this phrase in a real GMAT question.geet wrote:There are 100 employees in a company. Is the salary range greater than $1,000,000?
(1) The range to the median is less than $400,000.
(2) The standard deviation is $200,000
OA l8r ....do explain your logic!!!
Statement 2 is certainly insufficient, however; it's certainly possible to have a range greater than $1,000,000 and a standard deviation of $200,000, though the only way to prove that is using Chebyshev's inequality, which is certainly not tested on the GMAT. It's also easy to design a set with a range less than $1,000,000 and a standard deviation of $200,000. It's a very poorly designed question (and it's even worse if the OA is D, which is clearly wrong), and not one you need to study for the GMAT - where is it from?
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com
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mehravikas
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Great explanation !! Thanks Ian
Ian Stewart wrote:This question doesn't make any sense. The 'range to the median' is meaningless; the range from what to the median? The least value in the set? The largest value in the set? There's no way to decide if this is sufficient, since there's no way to know what it means. At a guess, I'd suppose they're trying to say that no value is more than $400,000 from the median, in which case the range can't be greater than $800,000, but you'd never see this phrase in a real GMAT question.geet wrote:There are 100 employees in a company. Is the salary range greater than $1,000,000?
(1) The range to the median is less than $400,000.
(2) The standard deviation is $200,000
OA l8r ....do explain your logic!!!
Statement 2 is certainly insufficient, however; it's certainly possible to have a range greater than $1,000,000 and a standard deviation of $200,000, though the only way to prove that is using Chebyshev's inequality, which is certainly not tested on the GMAT. It's also easy to design a set with a range less than $1,000,000 and a standard deviation of $200,000. It's a very poorly designed question (and it's even worse if the OA is D, which is clearly wrong), and not one you need to study for the GMAT - where is it from?
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PussInBoots
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Thanks Ian, I was on the same page. Some forum members should really learn the definitions of median, standart deviation, and mean before answering questions.
