If S is a finite set of consecutive even numbers, is the median of S an odd number?
(1) The mean of set S is an even number.
(2) The range of set S is divisible by 4.
Any useful/quick way for verifying 2?
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sam2304
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In an equally spaced set mean = median. So if mean is even median is even. NO. SUFFIf S is a finite set of consecutive even numbers, is the median of S an odd number?
(1) The mean of set S is an even number.
Range is a multiple of 4.(2) The range of set S is divisible by 4.
2 4 6
2 4 6 8 10
So the set has odd number of values and median will always be the mid one which is even. SUFF
IMO D.
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bryan88
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By your reasoning A is sufficient as it answers Yes /No
sam2304 wrote:In an equally spaced set mean = median. So if mean is even median is even. NO. SUFFIf S is a finite set of consecutive even numbers, is the median of S an odd number?
(1) The mean of set S is an even number.
Range is a multiple of 4.(2) The range of set S is divisible by 4.
2 4 6
2 4 6 8 10
So the set has odd number of values and median will always be the mid one which is even. SUFF
IMO D.
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sam2304
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I don't get your query. If you are asking whether it is sufficient, then YES it is by itself sufficient.bryan88 wrote:By your reasoning A is sufficient as it answers Yes /No
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bryan88
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I think A is sufficient because the mean/median of consecutive integers cannot be an integer if the number of integers is even.
IMO we dont need to check for "even" / "odd".
Experts help
IMO we dont need to check for "even" / "odd".
Experts help
sam2304 wrote:I don't get your query. If you are asking whether it is sufficient, then YES it is by itself sufficient.bryan88 wrote:By your reasoning A is sufficient as it answers Yes /No
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Brent@GMATPrepNow
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You're right in saying that the mean/median of consecutive integers cannot be an integer if the number of integers is even. However, the question involves a "set of consecutive even numbers."bryan88 wrote:I think A is sufficient because the mean/median of consecutive integers cannot be an integer if the number of integers is even.
IMO we dont need to check for "even" / "odd".
Experts helpsam2304 wrote:I don't get your query. If you are asking whether it is sufficient, then YES it is by itself sufficient.bryan88 wrote:By your reasoning A is sufficient as it answers Yes /No
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With evenly spaced integers:bryan88 wrote:If S is a finite set of consecutive even numbers, is the median of S an odd number?
(1) The mean of set S is an even number.
(2) The range of set S is divisible by 4.
Any useful/quick way for verifying 2?
Median = mean = (biggest+smallest)/2.
Statement 1: The mean of set S is an even number.
Since median = mean, the median is an even number.
SUFFICIENT.
Statement 2: The range of set S is divisible by 4.
Let b = the biggest integer and s = the smallest.
Since b-s = 4k, b = s+4k.
Thus, the median = (b+s)/2 = ((s+4k) + s)/2 = s + 2k.
Since s and 2k are both even, the median is even.
SUFFICIENT.
The correct answer is D.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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