If x, y, and z are positive integers and 3x = 4y = 7z, then the least possible value of x + y + z is
(A) 33
(B) 40
(C) 49
(D) 61
(E) 84
The answer is D
I have no clue how to solve this one
Least possible value
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3x=4y=7zmadsport wrote:how did you come up with this arrangement --->x=4*7, y=3*7, z=3*4?
LCM = 84
x = 28
y = 21
z = 12
28+21+12 = 61
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3x=4y=7z
z=3x/7
y=3x/4
x + y + z = x + 3x/4 + 3x/7 = 61x/28
to make 61x/28 an integer minimum value of x is 28, because 61 is prime number
so 28 + 30*28/4 + 3*28/7 = 61
Answer D
z=3x/7
y=3x/4
x + y + z = x + 3x/4 + 3x/7 = 61x/28
to make 61x/28 an integer minimum value of x is 28, because 61 is prime number
so 28 + 30*28/4 + 3*28/7 = 61
Answer D