Is y < (x+z)/2 ?

This topic has expert replies
User avatar
Junior | Next Rank: 30 Posts
Posts: 28
Joined: Wed Feb 14, 2007 12:25 am
Thanked: 1 times
GMAT Score:690

Is y < (x+z)/2 ?

by Andrei » Fri Oct 30, 2009 9:05 am
Hi,

I found the following problem in the Gmatprep test:

Is y < (x+z)/2?

1) y - x < z - y
2) z - y > (z- x)/2

OA is D.


I tried the following way:
1. y - x < z - y => 2y < Z +x => y < (z+x)/2 - SUFFICIENT

2. z - y > (z -x)/2 => 2z - 2y > z -x => z + x > 2y
=> (z+x)/2 > y - SUFFICIENT

So, the answer should be D.

BUT ... the above rationale is correct only if x,y,z are positive, so the signs of the inequalities do not change.
Please help, thanks.

Master | Next Rank: 500 Posts
Posts: 177
Joined: Thu Aug 14, 2008 11:59 am
Thanked: 25 times

by mp2437 » Fri Oct 30, 2009 9:46 am
Isn't the answer B?

Junior | Next Rank: 30 Posts
Posts: 10
Joined: Sun Oct 25, 2009 2:09 pm
Thanked: 2 times

Re: Is y < (x+z)/2 ?

by ayashlaha » Fri Oct 30, 2009 11:00 am
Andrei wrote:Hi,

I found the following problem in the Gmatprep test:

Is y < (x+z)/2?

1) y - x < z - y
2) z - y > (z- x)/2

OA is D.


I tried the following way:
1. y - x < z - y => 2y < Z +x => y < (z+x)/2 - SUFFICIENT

2. z - y > (z -x)/2 => 2z - 2y > z -x => z + x > 2y
=> (z+x)/2 > y - SUFFICIENT

So, the answer should be D.

BUT ... the above rationale is correct only if x,y,z are positive, so the signs of the inequalities do not change.
Please help, thanks.
Hi Andrei,

Your logic is correct. In either case you are dividing by 2 ( a positive number)

Additions,subtractions and (dividion or multiplication by positive numbers) do not require you to change directions of the inequality.

Hope this helps.