Hi,
I found the following problem in the Gmatprep test:
Is y < (x+z)/2?
1) y - x < z - y
2) z - y > (z- x)/2
OA is D.
I tried the following way:
1. y - x < z - y => 2y < Z +x => y < (z+x)/2 - SUFFICIENT
2. z - y > (z -x)/2 => 2z - 2y > z -x => z + x > 2y
=> (z+x)/2 > y - SUFFICIENT
So, the answer should be D.
BUT ... the above rationale is correct only if x,y,z are positive, so the signs of the inequalities do not change.
Please help, thanks.
Is y < (x+z)/2 ?
This topic has expert replies
Hi Andrei,Andrei wrote:Hi,
I found the following problem in the Gmatprep test:
Is y < (x+z)/2?
1) y - x < z - y
2) z - y > (z- x)/2
OA is D.
I tried the following way:
1. y - x < z - y => 2y < Z +x => y < (z+x)/2 - SUFFICIENT
2. z - y > (z -x)/2 => 2z - 2y > z -x => z + x > 2y
=> (z+x)/2 > y - SUFFICIENT
So, the answer should be D.
BUT ... the above rationale is correct only if x,y,z are positive, so the signs of the inequalities do not change.
Please help, thanks.
Your logic is correct. In either case you are dividing by 2 ( a positive number)
Additions,subtractions and (dividion or multiplication by positive numbers) do not require you to change directions of the inequality.
Hope this helps.