Is integer N even?
1) NxN=N
2)N=N^3
Is integer N even?
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- kmittal82
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(1)
nxn = n
n(n - 1 ) = 0
This means either n=0, or n = 1. Not sufficient
(2)
n - (n^3) = 0
n(1 - n^2) = 0
n(1-n)(1+n)=0
This means n=0, or n=1 or n = -1. Not sufficient
Combining (1) and (2), we get either n=0 or n=1, again, not sufficient
So (E)
Note: I'm considering 0 to be an even number here, i.e. 0 divided by 2 leaves a remainder of 0
nxn = n
n(n - 1 ) = 0
This means either n=0, or n = 1. Not sufficient
(2)
n - (n^3) = 0
n(1 - n^2) = 0
n(1-n)(1+n)=0
This means n=0, or n=1 or n = -1. Not sufficient
Combining (1) and (2), we get either n=0 or n=1, again, not sufficient
So (E)
Note: I'm considering 0 to be an even number here, i.e. 0 divided by 2 leaves a remainder of 0
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Should zero always be considered an even no.?
Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?
Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?
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Hi,Spartacus2000 wrote:Should zero always be considered an even no.?
Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?
Yes...Zero is always even.
If set X contains even numbers less than 10, you should consider zero as well. But, if set X contains positive even numbers less than 10, then you shouldn't consider zero because zero is neither positive nor negative.
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Things are not what they appear to be... nor are they otherwise
- kmittal82
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I believe so. No matter what the test, it shouldn't change the fundamental definition of what is an even number, i.e. a number when divided by 2 leaving no remainder. 0 certainly fits this.Spartacus2000 wrote:Should zero always be considered an even no.?
Does that apply for all questions eg: Set X contains even nos. < 10, in that case can zero be considered a part of this set?