is 1/k > 0?

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is 1/k > 0?

by vzzai » Fri Nov 25, 2011 9:50 pm
If k is not equal to 0, 1, or -1, is 1/k > 0?

(1)1/(k+1)> 0

(2)1/(k-1)> 0

Unconfirmed OA is D. I went for A. Please explain.
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by shankar.ashwin » Fri Nov 25, 2011 11:36 pm
1/k will be > 0, when k is +ve.

Statement 1:

1/(k+1) > 0

This condition satisfies for all values of k>1.

But, condition also satisfies when k = -1/2. k can be +ve or -ve - Insufficient

Statement 2:

1/(k-1) > 0

k can take any value > 1 to satisfy this condition. (Given k cannot be 1)
Thus k should be +ve and > 1. Sufficient.

Answer should be B IMO. Note : Question does not mention k is an integer.

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by vzzai » Sat Nov 26, 2011 2:36 am
I agree with you shankar.ashwin. I took K as integer! .
Thank you,
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by Ian Stewart » Sat Nov 26, 2011 6:42 am
vzzai wrote:If k is not equal to 0, 1, or -1, is 1/k > 0?

(1)1/(k+1)> 0

(2)1/(k-1)> 0

Unconfirmed OA is D. I went for A. Please explain.
"1/k > 0" means exactly the same thing as "k > 0". Similarly, 1/(k+1) > 0 just means that k + 1 > 0, or that k > -1. So Statement 1 is not sufficient. Since 1/(k-1) > 0 just means that k - 1 > 0, or that k > 1, Statement 2 is sufficient.
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