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integers

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integers

by divya23 » Tue Jun 14, 2011 4:40 am
If x<0,then sqrt(-x|x|) is
-x
-1
1
x
sqrtx

[spoiler]OA = 1[/spoiler]
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by Frankenstein » Tue Jun 14, 2011 4:50 am
Hi,
|x| = -x for x<0
So, sqrt(-x|x|) = sqrt(-x(-x)) = |x|, as sqrt is always non-negative.
= -x

Hence, 1
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by GMATGuruNY » Tue Jun 14, 2011 5:17 am
divya23 wrote:If x<0,then √(-x|x|) is
-x
-1
1
x
sqrtx

[spoiler]OA = 1[/spoiler]
Let x = -2.
√(-(-2)*|-2|) = √(2*2) = 2. This is our target.

Now we plug x=-2 into the answers to see which yields our target of 2.

Only answer choice A works:
-x = -(-2) = 2.

The correct answer is A.
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