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Consider side of square ABCD = 4 (Area = 16)
Now side of square = Diameter of circle O
Diameter of circle O = Diagonal of square EFGH.
2*Side^2 (EFGH) = 16 (Phy Theorem)
Area(EFGH) = Side^2 = 16/2 = 8.
Now Area ABCD/ Area EFGH = 16/8 = 2:1
Now side of square = Diameter of circle O
Diameter of circle O = Diagonal of square EFGH.
2*Side^2 (EFGH) = 16 (Phy Theorem)
Area(EFGH) = Side^2 = 16/2 = 8.
Now Area ABCD/ Area EFGH = 16/8 = 2:1
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MBA.Aspirant wrote:how to approach this one?
Solution:
Let the side of the square ABCD be 2s.
Hence, the diagonal of the square EFGH is 2s.
This means that the side of the square is 2s/(sqrt2) = (sqrt2)s.
This means that the ratio of the sides of the square is 2s:(sqrt2)s = sqrt2:1.
Hence, the ratio of the areas of the square is (sqrt2)^2:1^2 = 2:1
Anurag Mairal, Ph.D., MBA
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