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If xy≠0, is (x^3 y^2)/(x^2 y^3 )=1?

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If xy≠0, is (x^3 y^2)/(x^2 y^3 )=1?

by Max@Math Revolution » Mon Jan 18, 2016 9:03 pm
If xy≠0, is (x^3 y^2)/(x^2 y^3 )=1?


1) x^2/y^2 =1
2) x^3/y^3 =1


* A solution will be posted in two days.
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by GMATinsight » Thu Jan 21, 2016 10:26 am
Max@Math Revolution wrote:If xy≠0, is (x^3 y^2)/(x^2 y^3 )=1?


1) x^2/y^2 =1
2) x^3/y^3 =1


* A solution will be posted in two days.
Question : (x^3 y^2)/(x^2 y^3 )=1?

Question : (x)/(y)=1?

Statement 1: x^2/y^2 =1

x/y = +1
NOT SUFFICIENT

Statement 2: x^3/y^3 =1
i.e. x/y = +1
SUFFICIENT

Answer: Option B
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by Matt@VeritasPrep » Fri Jan 22, 2016 4:03 pm
S1::

x²/y² = 1 ->

x² = y² ->

x³y²/x²y³ = x�/(x�*y) = x/y

But since (x/y)² = 1, we could have (x/y) = 1 or (x/y) = -1.

S2::

x³ = y³ ->

x³y²/x²y³ = y³y²/x²y³ = y²/x²

Since (x/y)³ = 1, we have (x/y) = 1, or y = x, so (y/x)² = 1.
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by Max@Math Revolution » Mon Jan 25, 2016 4:46 pm
If xy≠0, is (x^3 y^2)/(x^2 y^3 )=1?

1) x^2/y^2 =1
2) x^3/y^3 =1


When you modify the original condition and the question, they become (x^3 y^2)/(x^2 y^3 )=1?--> x/y=1?.

1) x/y=-1 no, x/y=1 yes, which is not sufficient.
2) x/y=1 yes, which is sufficient. Therefore, the answer is B.


� Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
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by Max@Math Revolution » Wed Jan 27, 2016 5:33 pm
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If xy≠0, is (x^3 y^2)/(x^2 y^3 )=1?

1) x^2/y^2 =1
2) x^3/y^3 =1


When you modify the original condition and the question, they become (x^3 y^2)/(x^2 y^3 )=1?--> x/y=1?.
For 1), x/y=-1 -> no, x/y=1 -> yes, which is not sufficient.
For 2), x/y=1 -> yes, which is sufficient. Therefore, the answer is B.


� Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
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