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if X>1 and Y>1, is X<Y?

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if X>1 and Y>1, is X<Y?

by gmat740 » Fri Aug 07, 2009 10:23 am
if X>1 and Y>1, is X<Y?

(1) X^2/(XY+X)<1
(2) XY/Y^2-Y<1

[spoiler]IMO-B
OA-E[/spoiler]
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by tim0thy » Fri Aug 07, 2009 1:46 pm
I got B also. What's the source?
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by gmat740 » Fri Aug 07, 2009 5:03 pm
I believe this to be a GMAT prep Question, but not sure as I copied it from the other forum(TestMagic)
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by adssaini » Sat Aug 08, 2009 5:07 am
I also go with B
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hmm

by JeffB » Sat Aug 08, 2009 1:45 pm
if X>1 and Y>1, is X<Y?

(1) X^2/(XY+X)<1
(2) XY/Y^2-Y<1

(1) X^2/(XY+X)<1
X^2 < XY + X
X < Y + 1

(2)XY/Y^2 - Y < 1
XY/Y^2 < Y + 1
XY/Y < Y(Y+1)
X < Y(Y+1)

I would go with E.
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by real2008 » Sun Aug 09, 2009 7:04 am
(2) XY/Y^2-Y<1

Mind it is (XY/Y^2)-Y<1

not, XY/(Y^2-Y)<1

so E
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Re: if X>1 and Y>1, is X<Y?

by mehravikas » Thu Aug 13, 2009 11:17 pm
Is it -

XY/Y^2-Y<1

OR

XY/(Y^2-Y)<1
gmat740 wrote:if X>1 and Y>1, is X<Y?

(1) X^2/(XY+X)<1
(2) XY/Y^2-Y<1

[spoiler]IMO-B
OA-E[/spoiler]
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by pavell » Fri Aug 14, 2009 12:26 am
E
we can't reduce X ( a) or Y(b) becouse don't know x and y even or odd
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Agree with E

by mark412 » Mon Aug 17, 2009 2:37 pm
I would go with E. The trick is we cannot multiply the divisor with a variable whose sign we do not know. If it is negative, that could change how the equality is represented. Since we do not know the sign for either x or y, we cannot assume they are positive.


Answer is E
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Re: if X>1 and Y>1, is X<Y?

by yezz » Mon Aug 17, 2009 3:29 pm
gmat740 wrote:if X>1 and Y>1, is X<Y?

(1) X^2/(XY+X)<1
(2) XY/Y^2-Y<1

[spoiler]IMO-B
OA-E[/spoiler]
1) x/y+1<1 ie: x<y+1...insuff

from 2

x/y-1 <1 ie: x<y-1...suff

OE is wrong
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