DS pb # 116.
if 75% of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee?
1. 60 % of guests who ordered dessert also ordered coffee
2. 90% of the guests who ordered coffee also ordered dessert
the answer explanation assumes that each guest ordered either dessert or coffee but that is not given in the question, how can we assume that?
Anyways, can someone pls explain. Thanks
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Let D = total who ordered dessert.If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee?
1.) 60% of the guests who ordered dessert also ordered coffee.
2.) 90% of the guests who ordered coffee also ordered dessert.
Let C = total who ordered coffee.
Let B = total who ordered both dessert and coffee.
Plug in guests = 100.
Then D = .75*100 = 75.
Statement 1: 60% of the guests who ordered dessert also ordered coffee.
B = .6*75 = 45.
Not way to determine C.
Insufficient.
Statement 2: 90% of the guests who ordered coffee also ordered dessert.
.9C = B.
Not way to determine C.
Insufficient.
Statements 1 and 2 together:
.9C = 45.
C = 50.
Sufficient.
The correct answer is C.
The solution tells us the following:
45 ordered both coffee and dessert.
50-45 = 5 ordered only coffee.
75-45 = 30 ordered only dessert.
Thus, 100-45-5-30 = 20 ordered neither coffee nor dessert.
The solution does not assume that every guest ordered coffee or dessert. Given the values above, 20 ordered neither.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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