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imago Just gettin' started!
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Posted: Sun Sep 16, 2007 12:29 pm Post subject: If N = 10^10 |
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If N= 10 ^100 and N^N= 10 ^k
What is the value of k?
a. 200
b.10^100
c.10^102
d.100^100
e.100^10^100 |
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niks_01.27 Rising GMAT Star

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Posted: Sun Sep 16, 2007 1:10 pm Post subject: |
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Substitute the value of both N's in;
N^N = 10^k.
You will get k = 10^102. _________________ regards
niks... |
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optimisticsam Rising GMAT Star
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Posted: Sun Sep 16, 2007 1:23 pm Post subject: |
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| Little fuzzy on this one still - anyone care to explain a little further? |
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kajcha GMAT Destroyer!
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Posted: Sun Sep 16, 2007 1:49 pm Post subject: |
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(x^y)^z can be written as (x)^(y*z).
In this case N = 10^100
N^N = (10^100)^(10^100) = 10^k
= 10^(100*(10^100)) = 10^k
k = 100*(10^100) => (10^2)*(10^100) = 10^102 |
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imago Just gettin' started!
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Posted: Sun Sep 16, 2007 3:33 pm Post subject: |
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| kajcha wrote: | (x^y)^z can be written as (x)^(y*z).
In this case N = 10^100
N^N = (10^100)^(10^100) = 10^k
= 10^(100*(10^100)) = 10^k
k = 100*(10^100) => (10^2)*(10^100) = 10^102 |
Thanks Kajcha is very clear! |
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optimisticsam Rising GMAT Star
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Posted: Sun Sep 16, 2007 3:58 pm Post subject: |
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Ah! Got it. Thanks!
I was forgetting that (x^a)(x^b) = x^(a+b)
Thanks for clarifying! Very helpful! |
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