(n>=1), what is a6?
(1)a6-a5=3
(2)a7+a8=34
The answer is c. I don't know how to look at statement (2)
If an+2=an+an+1
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n>=1), what is a6?
(1)a6-a5=3
(2)a7+a8=34
(1)
means that succesive term is 3 greater than preceding. It is difference between neighbouring terms
UNSUFF to find the value of a6
(2)
Sum of neighbouring terms
UNSUFF to find the value of a6
(1)(2)
a6 + 3 = a7
a6 + 3 + 3 = a8
2*a6 + 9 = 34
a6 can easily be found
C
(1)a6-a5=3
(2)a7+a8=34
(1)
means that succesive term is 3 greater than preceding. It is difference between neighbouring terms
UNSUFF to find the value of a6
(2)
Sum of neighbouring terms
UNSUFF to find the value of a6
(1)(2)
a6 + 3 = a7
a6 + 3 + 3 = a8
2*a6 + 9 = 34
a6 can easily be found
C
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- Junior | Next Rank: 30 Posts
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