Magoosh
The microcurrent through the electrode in a dedicate circuit is usually held constant at \(3.6\cdot 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?
A. \(3.6\cdot 10^{-8000}\)
B. \(3.6\cdot 10^{-24}\)
C. \(3.6\cdot 10^{-11}\)
D. \(3.6\cdot 10^{-5}\)
E. \(3.6\cdot 10^{-8/3}\)
OA C
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The microcurrent through the electrode in a dedicate circuit
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Scott@TargetTestPrep
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AAPL wrote:Magoosh
The microcurrent through the electrode in a dedicate circuit is usually held constant at \(3.6\cdot 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?
A. \(3.6\cdot 10^{-8000}\)
B. \(3.6\cdot 10^{-24}\)
C. \(3.6\cdot 10^{-11}\)
D. \(3.6\cdot 10^{-5}\)
E. \(3.6\cdot 10^{-8/3}\)
OA C
3.6 x 10^(-8) x 1/1000
Noting that 1/1000 = 10^-3, we have:
= 3.6 x 10^(-8) x 10^(-3)
= 3.6 x 10^(-11)
Answer: C
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Brent@GMATPrepNow
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Key concept #1: If X is 1000 times smaller than Y, we can write: X = Y/1000AAPL wrote:Magoosh
The microcurrent through the electrode in a dedicate circuit is usually held constant at \(3.6\cdot 10^{-8}\) amps. Because of a defect in another part of the circuit, the current was 1,000 times smaller. What was the current, in amps, caused by this defect?
A. \(3.6\cdot 10^{-8000}\)
B. \(3.6\cdot 10^{-24}\)
C. \(3.6\cdot 10^{-11}\)
D. \(3.6\cdot 10^{-5}\)
E. \(3.6\cdot 10^{-8/3}\)
OA C
Key concept #2: (ab)/c = (a)(b/c)
So, the measure of the resulting current = (3.6)[10^(−8)]/1000
Rewrite as: (3.6)[10^(−8)]/(10^3)
Use Concept #2 to rewrite as: (3.6)[10^(−8)/10^3]
Apply Quotient Law for exponents to get: (3.6)[10^(−8−3)]
Simplify: (3.6)[10^(−11)]
Answer: C
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Brent
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