I need help to solve it.........

This topic has expert replies
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Thu Oct 16, 2008 3:17 am
Thanked: 1 times

I need help to solve it.........

by Alfred » Mon Jan 18, 2010 12:59 am
Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.
Thanks

User avatar
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Fri Oct 30, 2009 9:13 pm

by swati chaturvedi » Mon Jan 18, 2010 1:45 am
answer seems to be '4'

1. divisible by 5 -----

when 9446 is divided by 5,this leaves remainder of 1 and both 4 and 9 will satisfy the condition of n divisible by 5.

9446/5= 1889 1/5

2. divisible by 9-----

9446/9= 1049 5/9, with remainder of 5 and only 4 will satisfy this condition of n being divisible by 9.

Hope it is correct.

Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Sat Dec 26, 2009 12:22 pm
Location: Noida, India

by mun1shk » Mon Jan 18, 2010 2:39 pm
Alfred wrote:Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.
Thanks
Hi Alfred,

Remember the divisibility test of 9, if a number is given then you add up all the digits and see if the result is divisible by 9.
eg 72 = 7+2=9 so divisible by 9

for this question Ans should be D both statements will give answer 4.

Junior | Next Rank: 30 Posts
Posts: 14
Joined: Tue Nov 10, 2009 10:39 am
Thanked: 1 times

by Concordio » Fri Jan 22, 2010 11:55 pm
I think the answer is B. (1) is insufficient because it gives you two answers - 4 or 9. (2) only gives you 4 as a viable answer choice.

Junior | Next Rank: 30 Posts
Posts: 24
Joined: Tue Nov 03, 2009 11:07 am

by tata » Mon Jan 25, 2010 11:25 am
The question is a little confusing, does the question mean 1 and 9 ARE included? If it does then the answer is B, if 1 and 9 are EXCLUDED i.e 1<c<9 then the answer is D

mun1shk wrote:
Alfred wrote:Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.
Thanks
Hi Alfred,

Remember the divisibility test of 9, if a number is given then you add up all the digits and see if the result is divisible by 9.
eg 72 = 7+2=9 so divisible by 9

for this question Ans should be D both statements will give answer 4.

User avatar
Legendary Member
Posts: 1022
Joined: Mon Jul 20, 2009 11:49 pm
Location: Gandhinagar
Thanked: 41 times
Followed by:2 members

by shashank.ism » Fri Feb 19, 2010 5:41 am
Alfred wrote:Hello friends

This is a question of arithmetic related to number problems, I have tried a lot to solve it but somehow I am unable to find out the correct answer.

If c is a +ve integer between 1 and 9, and n = 9,446 + c, then what is the value of c?
(1) n is divisible by 5.
(2) n is divisible by 9.
In the last paragraph, when n is divisible by 5, then "c" can be 4 or 9. In the next sentence it states, "if n is divisible by 9, you can add the digits and find what
the nearby multiples of 9 are. Which digits are you adding?

I had seen this question at www.testcircle.com/gmat in free GMAT sample videos, and there are more than 1000s of GMAT CAt test based questions in free sample videos.
Waiting for a good reply.Thanks
here n = 9446 + c
st.1: when 9446 is divided by 5 it will give remainder =1 (as last digit is 6)
so for 9446 + c to be divisible by 5, c+1 must be divisible by 5
also1< c<9 --> c= 4 -----------------(i)--------------sufficient

st.2: also when 9446 is divided by 5 it will give remainder =5 (as last sum of digit = 9+4+4+6 = 23)
so for 9446 + c to be divisible by 9, c+5 must be divisible by 9
also1=< c<=9 --> c= 4 -----------------(ii)--------------sufficient

Ans D
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.

User avatar
Senior | Next Rank: 100 Posts
Posts: 90
Joined: Fri Jan 22, 2010 1:10 pm
Location: New Jersey
Thanked: 13 times
Followed by:4 members
GMAT Score:640

by Mom4MBA » Fri Feb 19, 2010 8:42 am
Shashank is right here, actually the confusion here is in statement 1, because it is written between 1 and 9 that means 1 and 9 are not included.

so both the statements are sufficient alone, giving us answer D
Last edited by Mom4MBA on Fri Feb 19, 2010 10:08 am, edited 1 time in total.
Stay focused

User avatar
Legendary Member
Posts: 1022
Joined: Mon Jul 20, 2009 11:49 pm
Location: Gandhinagar
Thanked: 41 times
Followed by:2 members

by shashank.ism » Fri Feb 19, 2010 10:04 am
Mom4MBA wrote:Shashank's is right here, actually the confusion here is in statement 1, because it is written between 1 and 9 that means 1 and 9 are not included.

so both the statements are sufficient alone, giving us answer D
Yeah that is what I meant to say that If its clearly written between 1 and 9 that means 1 and 9 are not included.
Also I have seen that whenever there is an inclusion of boundary values they always specify it in question or show it inform of mathematical expression so rest assured about it...
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.

Newbie | Next Rank: 10 Posts
Posts: 8
Joined: Sun Mar 15, 2009 4:37 am
Location: India

by rohankelkar81 » Sat Feb 20, 2010 3:14 am
hi all,

I guess the answer is 'B'.... since that is precisely concludes the value of 'c'. n we dont need other hint for doing them.. it also takes care of optimization
Victorious!
Rohan

User avatar
Legendary Member
Posts: 1022
Joined: Mon Jul 20, 2009 11:49 pm
Location: Gandhinagar
Thanked: 41 times
Followed by:2 members

by shashank.ism » Sat Feb 20, 2010 5:08 am
rohankelkar81 wrote:hi all,

I guess the answer is 'B'.... since that is precisely concludes the value of 'c'. n we dont need other hint for doing them.. it also takes care of optimization
rohankelkar81 yeah B precisely concludes the value of C but A also gives the same value...
so you have to consider the option D which says" A and B are individually sufficient to ans he problem"
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.