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Exponent Question

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Newbie | Next Rank: 10 Posts
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Exponent Question

by KFreudenberg » Fri May 14, 2010 3:53 pm
(1001^2 - 999^2) / (101^2 - 99^2) = ?

I have the answer for the above problem, but could use some guidance on an easy way to find this answer.

Thanks!!
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by gmatjedi » Fri May 14, 2010 4:46 pm
as follows:
=(1001^2 - 999^2) / (101^2 - 99^2)
=[(1001-999)(1001+999)]/[(101-99)(101+99)]
=[(2*2000)]/[(2*200)]
=10
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by KFreudenberg » Fri May 14, 2010 6:03 pm
ah! this is helpful..

for anyone else the rule is: x^2 - y^2 = (x - y)(x + y)
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