2k = pw - 2w^2
2w^2 - pw + 2k = 0
I thought subtracting 2k from each side would end up a (-) sign in front of 2k, not (+) in front of 2k = 0. Can someone please tell me the rule to this?
Thank You,
BV
How Did This Problem Change Signs?
This topic has expert replies
- BlindVision
- Master | Next Rank: 500 Posts
- Posts: 253
- Joined: Fri Dec 26, 2008 8:39 pm
- Thanked: 8 times
- Followed by:1 members
- BlindVision
- Master | Next Rank: 500 Posts
- Posts: 253
- Joined: Fri Dec 26, 2008 8:39 pm
- Thanked: 8 times
- Followed by:1 members
Thanks for you help. I'm still not getting how a (+) is in front of 2K, even if they subtracted (pw - 2w^2) from both sides. I'm not getting the rule. My brain is having a slow day.lol
Life is a Test
- Neo2000
- Legendary Member
- Posts: 519
- Joined: Sat Jan 27, 2007 7:56 am
- Location: India
- Thanked: 31 times
2k - (pw - 2w^2) = (pw - 2w^2 ) - (pw - 2w^2)
The left hand side now becomes
2k - pw - (-2w^2) which is = 2k - pw + 2w^2
Re-arranging these terms you get
2w^2 - pw + 2k
Since no operation was performed on 2k, 2k retains its original "+" value.
The left hand side now becomes
2k - pw - (-2w^2) which is = 2k - pw + 2w^2
Re-arranging these terms you get
2w^2 - pw + 2k
Since no operation was performed on 2k, 2k retains its original "+" value.
- BlindVision
- Master | Next Rank: 500 Posts
- Posts: 253
- Joined: Fri Dec 26, 2008 8:39 pm
- Thanked: 8 times
- Followed by:1 members