If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?
A. (201)^2/t
B. {(202)(201)}/t
C. 201/t
D. 202/t
E. (202)(201)/t^2
t = s*201.
We can plug in any values for s and t that satisfy this relationship.
Let s = 2.
Then t = 2*201 = 402.
1/s + 1/t = 1/2 + 1/402 = 402/804 + 2/804 = 404/804 = 101/201. This is our target.
Now we plug t=402 into the answers to see which yields our target of 101/201.
Only answer choice D works:
202/t = 202/402 = 101/201.
The correct answer is
D.
As X increases from 165 to 166,which of the following must increase?
i)2x-5
ii)1-1/x
iii)1/(x^2-x)
A) i only
B)iii only
C)i and ii
d)i and iii
e) ii and iii
Ignore the values given. The question becomes:
As x increases, which of the following must also increase?
Plug in x=2 and x=3.
I. 2x-5
If x=2, then 2x-5 = 2*2 - 5 = -1.
If x=3, then 2x-5 = 2*3 - 5 = 1.
The value of 2x-5 increases.
Eliminate any answer choice that does not include i. Eliminate B and E.
ii)1-1/x
If x=2, then 1 - 1/2 = 1/2.
If x=3, then 1 - 1/3 = 2/3.
The value of 1 - 1/x increases.
Eliminate any answer choice that does not include ii. Eliminate A and D.
The correct answer is
C.
Nycgrl wrote:If 1/2 of the air in a tank is removed with each stroke of a vacuum pump, what fraction of the original amount of air has been removed after 4 strokes ?
1.15/16
2. 7/8
3. 1/4
4- 1/8
5. 1/16
We can plug in a value for the tank. We should plug in a value that can be divided by 2 four times without yielding a fraction. (The answer choices lead us in the right direction: the biggest denominator is 16.)
Let tank = 16 units.
After the 1st stroke, 1/2*16 = 8 units are removed.
16-8 = 8 units are left.
After the 2nd stroke, 1/2*8 = 4 more units are removed.
8-4 = 4 units are left.
After the 3rd stroke, 1/2*4 = 2 more units are removed.
4-2 = 2 units are left.
After the last stroke, 1/2*2 = 1 more unit is removed.
2-1 = 1 unit is left.
Since only 1 unit is left, 16-1 = 15 total units were removed.
Total removed/Tank = 15/16.
The correct answer is
A.
A straight pipe 1 yard in length was marked off in
fourths and also in thirds. If the pipe was then cut into
separate pieces at each of these markings, which of
the following gives all the different lengths of the
pieces, in fractions of a yard?
(A)1/6 and 1/4 only
(B)1/4 and 1/3 only
(C)1/6 ,1/4 and 1/3
(D)1/12 ,1/6, and 1/4
(E)1/12, 1/6, and 1/3
Place all the markings over a common denominator of 12:
Since 4/12 - 3/12 = 1/12, the correct answer must include 1/12. Eliminate A, B and C.
Since the pieces at each end = 1/4, the correct answer must include 1/4. Eliminate E.
The correct answer is
D.
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