deck of cards

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deck of cards

by jain2016 » Mon Apr 11, 2016 10:05 am
It takes machine A x hours to manufacture a deck of cards that machine B can manufacture in y hours. If machine A operates alone for z hours and is then joined by machine B until 100 decks are finished, for how long will the two machines operate simultaneously?


A) 100xy-z/x+y

B) y(100x-z)/x+y

C) 100y(x-z)/x+y

D) x+y/100xy-z

E) x+y-z/100xy

OAB

Hi Experts ,

Please explain.

Thanks,

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by [email protected] » Mon Apr 11, 2016 10:17 am
Hi jain2016,

This question can be solved by TESTing VALUES.

Machine A takes X hours to make a deck of cards.
Machine B takes Y hours to make a deck of cards.

Since the answers are suitably complex-looking, let's choose really small, easy numbers to work with:

X = 1
Y = 2

So...
Machine A takes 1 hour to make a deck of cards
Machine B takes 2 hours to make a deck of cards
When both machines work together for 2 total hours, 3 decks of cards are made.

The question goes on to state that Machine A will work alone for Z hours, then be joined by Machine B until 100 decks are made.

Z = 1

In that first hour, Machine A will produce 1 deck of cards, leaving 99 decks to go. Since the two machines together can produce 3 decks every 2 hours, the remaining 99 decks will take...
2 hours x 33 sets = 66 hours.

We're looking for the answer that equals 66 when we plug in X=1, Y=2 and Z=1 into the answer choices.

While it "looks like" there's a lot of math to be done, most of the answers are way too small to be 66 (and it shouldn't take too long to figure that out). Only one answer equals 66

Final Answer: B

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by GMATGuruNY » Mon Apr 11, 2016 12:46 pm
It takes machine A x hours to manufacture a deck of cards that machine B can manufacture in y hours. If machine A operates alone for z hours and is then joined by machine B until 100 decks are finished, for how long will the two machines operate simultaneously?

a) (100xy - z)/(x+y)
b) y(100x - z)/(x+y)
c) (x+y)/(100xy - z)
d) xz(100y - z)/(x+y+z)
e) (x+y-z)/(100xy)
Let x = 1 hour.
Since A takes 1 hour to produce a deck, A's rate = 1 deck per hour.
Let y = 2 hours.

Let A complete the ENTIRE JOB.
Since A produces 1 deck per hour, the time for A to produce all 100 decks = 100 hours.
Thus, z=100.

The question stem asks for the time that A and B work together.
Since A completes the entire job, the number of hours that A and B work together = 0. This is our target.

Now plug x=1, y=2 and z=100 into the answers to see which yields our target of 0.
A quick scan reveals that only B works:
y(100x - z)/(x+y) = 2(100*1 - 100)/(1+2) = 0.

The correct answer is B.
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by Matt@VeritasPrep » Mon Apr 11, 2016 12:58 pm
We could also just use a rate-time equation here: Work = R * T.

Since we're making one deck of cards, Work = 1. That means that our equations are:

Machine A:
1 = R * x
1/x = R

Machine B:
1 = R * y
1/y = R

So the machines' rates are 1/x and 1/y of the job per hour, respectively.

In z hours, Machine A will do

z * (1/x) of the job, or (z/x) of the job. That means we have (100 - z/x) left to do. One more work equation gives

Work = R * T

(100 - z/x) = (1/x + 1/y) * T

We want to solve for T, so we just divide both sides by (1/x + 1/y), and we're done!

(100 - z/x) / (1/x + 1/y) = T

(100 - z/x) / (x + y)/xy = T

xy * (100 - z/x) / (x + y) = T

(100xy - zy) / (x + y) = T

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by jain2016 » Tue Apr 12, 2016 1:55 am
The question stem asks for the time that A and B work together.
Since A completes the entire job, the number of hours that A and B work together = 0. This is our target.
Hi GMATGuruNY ,

Thanks for your reply.

Just a quick question if x=1 hour and y=2 hours , then A and B work together will be 3. So why A and B work together =0 ?

Please explain.

Many thanks in advance.

SJ

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by jain2016 » Tue Apr 12, 2016 1:56 am
In that first hour, Machine A will produce 1 deck of cards, leaving 99 decks to go. Since the two machines together can produce 3 decks every 2 hours, the remaining 99 decks will take...
2 hours x 33 sets = 66 hours.
Hi Rich ,

Can you please explain the above part? How come 66 hours?

Many thanks in advance.

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by [email protected] » Tue Apr 12, 2016 9:59 am
Hi jain2016,

Using the VALUES I chose...

Machine A takes 1 hour to make a deck of cards
Machine B takes 2 hours to make a deck of cards
When both machines work together for 2 total hours, Machine A makes 2 decks and Machine B makes 1 deck... for a total of 3 decks every 2 hours.

Since we get 3 decks every 2 hours

(3 decks)(33) = 99 decks
(2 hours)(33) = 66 hours

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by Matt@VeritasPrep » Tue Apr 12, 2016 6:30 pm
jain2016 wrote:
The question stem asks for the time that A and B work together.
Since A completes the entire job, the number of hours that A and B work together = 0. This is our target.
Hi GMATGuruNY ,

Thanks for your reply.

Just a quick question if x=1 hour and y=2 hours , then A and B work together will be 3. So why A and B work together =0 ?

Please explain.

Many thanks in advance.

SJ
These are just hypothetical numbers that seem to have been chosen to lead to a convenient answer. y = 2 is the time it WOULD take B on its own if B were forced to work alone, but since A's rate was fast enough to complete the job solo, B didn't have to work at all.