Target Test Prep's 2024 GMAT Focus Edition prep is discounted for the BTG community!

Redeem
Target Test Prep
5-Day Free Trial
5-day free, full-access trial TTP

Available with Beat the GMAT members only code

MORE DETAILS
Target Test Prep
Magoosh
Magoosh
Study with Magoosh GMAT prep

Available with Beat the GMAT members only code

MORE DETAILS
Magoosh

GMAT Prep

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 21
Joined: Mon Dec 24, 2007 7:11 am

GMAT Prep

by cks » Mon Dec 24, 2007 4:56 pm
Pls explain
Attachments
q6.jpeg
Top
Master | Next Rank: 500 Posts
Posts: 214
Joined: Wed Nov 14, 2007 6:30 am
Thanked: 15 times

by sujaysolanki » Tue Dec 25, 2007 5:02 am
Picking numbers is best here

say x =15
2^15 - 2^13 = 2^13(4-1) = 2^13(3)

Hence D
Top
Senior | Next Rank: 100 Posts
Posts: 78
Joined: Thu Dec 06, 2007 4:16 pm
Location: NYC, NY
Thanked: 2 times

by preciousrain7 » Thu Dec 27, 2007 2:09 pm
sujaysolanki wrote:Picking numbers is best here

say x =15
2^15 - 2^13 = 2^13(4-1) = 2^13(3)

Hence D
Hi, I'd really appreciate it if you can explain how you get 2^13(4-1)

Thanks a lot

Sonia
Top
Master | Next Rank: 500 Posts
Posts: 128
Joined: Sat Nov 17, 2007 11:59 am
Thanked: 1 times

by cris » Thu Dec 27, 2007 3:13 pm
[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)

and we know:

(2^x)(3/4)= (2^13) (3)

x must be 15

I think this way is faster
Top
Master | Next Rank: 500 Posts
Posts: 128
Joined: Sat Nov 17, 2007 11:59 am
Thanked: 1 times

by cris » Thu Dec 27, 2007 3:15 pm
[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)

and we know:

(2^x)(3/4)= (2^13) (3)

x must be 15

I think this way is faster
Top
Senior | Next Rank: 100 Posts
Posts: 78
Joined: Thu Dec 06, 2007 4:16 pm
Location: NYC, NY
Thanked: 2 times

by preciousrain7 » Thu Dec 27, 2007 3:25 pm
cris wrote:[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)

and we know:

(2^x)(3/4)= (2^13) (3)

x must be 15

I think this way is faster
THANK YOU SO MUCH!!!!! I FINALLY GET IT!
Top
Post new topic Post Reply
• Page 1 of 1