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tanyajoseph
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givemeanid
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Let the 3 weights be x, y and z.
Median = middle value = y = 9
The three weights are x, 9 and z
Mean = 7
x + 9 + z = 21
x + z = 12
For x to be max, z needs to be minimized. The min value of z has to be 9 otherwise the median changes. That means x = 3 is the max possible weight of the lightest box.
Median = middle value = y = 9
The three weights are x, 9 and z
Mean = 7
x + 9 + z = 21
x + z = 12
For x to be max, z needs to be minimized. The min value of z has to be 9 otherwise the median changes. That means x = 3 is the max possible weight of the lightest box.
So It Goes
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cveluswamy
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600 * 500/10^6 to identify the cost per milligram.
Easiest way is 600 * 500/10^6 = 300000/10^6 Since 1 kilogram equals to 10^6. put the decimal points 6 digits from left which is 0.3
What is the OA?
Easiest way is 600 * 500/10^6 = 300000/10^6 Since 1 kilogram equals to 10^6. put the decimal points 6 digits from left which is 0.3
What is the OA?
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tanyajoseph
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maolivie
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for the first question:
x + z = 12. You stated that for the x to be minimum, z has to be 9 otherwise the median changes. I'm confused by this because if z was 11, x would be 1. Then we have 1, 9, 11. 9 is still the median. Whats up with that?
x + z = 12. You stated that for the x to be minimum, z has to be 9 otherwise the median changes. I'm confused by this because if z was 11, x would be 1. Then we have 1, 9, 11. 9 is still the median. Whats up with that?
https://www.AccuInvestor.com - my site!
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givemeanid
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maolivie wrote:for the first question:
x + z = 12. You stated that for the x to be minimum, z has to be 9 otherwise the median changes. I'm confused by this because if z was 11, x would be 1. Then we have 1, 9, 11. 9 is still the median. Whats up with that?
The question is asking for MAXIMUM possible value of LIGHTEST box.
So It Goes
