If y > = 0, what is the value of x?
1. |x - 3| >= y
2. |x - 3| <= - y
value of x?
This topic has expert replies
from 1:
|x-3|>= y, a non-negative number. Since, y it could be any number, x could take various values.
Not Sufficient
from 2:
|x-3|<= -y
since absolute value can never be negative, this is only possible, if y=0.
therefore x-3 = 0, x=3
Sufficient
IMO answer B
|x-3|>= y, a non-negative number. Since, y it could be any number, x could take various values.
Not Sufficient
from 2:
|x-3|<= -y
since absolute value can never be negative, this is only possible, if y=0.
therefore x-3 = 0, x=3
Sufficient
IMO answer B
"Choose to chance the rapids and dance the tides"
-
- Legendary Member
- Posts: 2326
- Joined: Mon Jul 28, 2008 3:54 am
- Thanked: 173 times
- Followed by:2 members
- GMAT Score:710
IMO Biamseer wrote:from 1:
|x-3|>= y, a non-negative number. Since, y it could be any number, x could take various values.
Not Sufficient
from 2:
|x-3|<= -y
since absolute value can never be negative, this is only possible, if y=0.
therefore x-3 = 0, x=3
Sufficient
IMO answer B
oops it has to be B. Seer explanation does all!
Last edited by gmatmachoman on Sat May 08, 2010 11:31 am, edited 1 time in total.
- harshavardhanc
- Legendary Member
- Posts: 526
- Joined: Sat Feb 21, 2009 11:47 pm
- Location: India
- Thanked: 68 times
- GMAT Score:680
st1: |x - 3| >= yneoreaves wrote:If y > = 0, what is the value of x?
1. |x - 3| >= y
2. |x - 3| <= - y
as y is a positive quantity and |x-3| > y .
implies that x-3 itself is a positive quantity and we can safely write it as x-3 > y . However, this doesn't give us an solid value for X. Hence, insufficient.
st2: |x - 3| <= - y
LHS of this is a modulus, which can be either 0 or positive number. However, on the RHS we have -y. Suppose, y is a non-zero number. In that case, RHS would become a negative quantity and cannot be equated to a modulus . Hence, y MUST be zero.
which will give us |X-3| = 0 or X = 3.
IMO B
Regards,
Harsha
Harsha