Problem Solving

charmingirl8 wrote:Can anyone solve this? The answer makes no sense to me...Thanks!

If circle A has 3 times the area of circle B, and circle B has one-sixth of the area of square WXYZ, what is the ratio of the area of a circle inscribed within WXYZ to that of the area of circle A?

A- PI/ 12

B- PI/6

C- PI/2

D- 2/PI

Answer is C

Take some time to understand wat i wrote....couldnt put it in more simpler words........i hope this explanation will help u understand the ques

Soln

Area of Circle A = Pi sq(R)

Area of Circle B = Pi sq(r)

Area Of Square = sq (a) [let ‘a’ is side of square ]

Area Of Circle inscribed in Square = Pi sq (a/2)

As
circle B has one-sixth of the area of square WXYZ

Pi sq(r) = 1/6 sq (a)

sq (a)= 6 Pi sq (r)

ATQ
ratio of the area of a circle inscribed within WXYZ to that of the area of circle A = [Pi * 6 Pi sq (r)] / 4* Pi sq(R)
As circle A has 3 times the area of circle B
So ratio = Pi /2

As Pi sq(R) = 3 * Pi sq(r)

E- 12PI

charmingirl8 wrote:Can anyone solve this? The answer makes no sense to me...Thanks!

If circle A has 3 times the area of circle B, and circle B has one-sixth of the area of square WXYZ, what is the ratio of the area of a circle inscribed within WXYZ to that of the area of circle A?

A- PI/ 12

B- PI/6

C- PI/2

D- 2/PI

E- 12PI