How is the easiest way to approach a problem like this?
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Thanks in advance
Since a square has 4 equal sides, plug in multiples of 4.The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2:3 , what is the ratio of the area of region R to the are of region S ?
A 25:16
B 24:25
C 5:6
D 4:5
E 4:9
Let's PLUG IN some values that meet the given conditions.The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2:3 , what is the ratio of the area of region R to the are of region S ?
A 25:16
B 24:25
C 5:6
D 4:5
E 4:9
Let's call the sides of the rectangle 2x and 3x. 2x + 3x = 5x is half of the perimeter of the rectangle.The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2:3 , what is the ratio of the area of region R to the are of region S ?
A 25:16
B 24:25
C 5:6
D 4:5
E 4:9