How many positive even integers less then 100 contain digits 4 or 7.
A.) 16
B.)17
C.)18
D.) 19
E.)20
I tried something as follows but am unable to get the correct answer.
first i started with 4
so 4, 40, 42, 44, 46, 48, 24, 64, 84 giving me 9 numbers that have a 4 and are even.
now using 7
70,72,74,76,78, since 7 is not even number it can not be in the second place so we have only 5 numbers
9 number + 5 numbers is only 14... that is not even answer choice... what numbers am i missing?
Even integers less then 100?
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damn it i was fixated on number starting with 4... and 7 only...
Is there any formula i could use here to avoid hicups as such?
thanks for the answer..
Is there any formula i could use here to avoid hicups as such?
thanks for the answer..
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I'd suggest being more systematic. Choose something to list and then stick with it. It ensures you don't forget any, and it makes counting easier. If you have to find a lot more numbers, then you can write out enough to see the pattern, and then just go based on the pattern. There isn't a formula exactly, but if you've done a few of these you're less likely to forget a large group.
In this problem, one way to write the list would be:
First, try the numbers that have 4 at the end:
4,14, 24,34, 44, 54, 64, 74, 84, 94 = 10 ways
Then the numbers that have 4 at the beginning
40, 42, (44), 46, 48, = 4 ways
Then the numbers that have 7 at the end, well none of those are even.
Then the numbers that have 7 at the beginning:
70, 72, (74), 76, 78 = 4 ways
In this problem, one way to write the list would be:
First, try the numbers that have 4 at the end:
4,14, 24,34, 44, 54, 64, 74, 84, 94 = 10 ways
Then the numbers that have 4 at the beginning
40, 42, (44), 46, 48, = 4 ways
Then the numbers that have 7 at the end, well none of those are even.
Then the numbers that have 7 at the beginning:
70, 72, (74), 76, 78 = 4 ways
- rishab1988
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My approach:
Find all integers ending in 4 [they re all even]
04[same as 4.This is logic],14,24,...94 [This is like counting from 0 to 9 [in tens digit]. Therefore no of integers both inclusive =9-0=9 +1 [for inclusive]=10
Now 40 42 46 48 [Do not count 44 - already included in first list].Total =4
Now 70 72 76 78 =4 [ 74 would be repeated.]
I didn't include any integers that have 7 as their units digit ,for they are all odd.
total integers = 10+4+4 =18
Find all integers ending in 4 [they re all even]
04[same as 4.This is logic],14,24,...94 [This is like counting from 0 to 9 [in tens digit]. Therefore no of integers both inclusive =9-0=9 +1 [for inclusive]=10
Now 40 42 46 48 [Do not count 44 - already included in first list].Total =4
Now 70 72 76 78 =4 [ 74 would be repeated.]
I didn't include any integers that have 7 as their units digit ,for they are all odd.
total integers = 10+4+4 =18
- anirudhbhalotia
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Very first thing is to read the question very carefully!
It says 4 or 7...not starting with 4 or 7, and also not 4 and 7!
Then I did the manual listing of nos. and counting. Since the range is 100, this is the least complicated way for me and also to not get confused.
For bigger ranges, I am not too sure of the approach.
It says 4 or 7...not starting with 4 or 7, and also not 4 and 7!
Then I did the manual listing of nos. and counting. Since the range is 100, this is the least complicated way for me and also to not get confused.
For bigger ranges, I am not too sure of the approach.