If a and b are 2 numbers and (|y|-a)(|y|-b)=0, then how many possible solution does y have?
1: a is negative
2: b is not negative
OA E
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mathewmithun
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|y| = a or |y| = b
S1 a<0 => meaningless solution
S2 b >= 0 => |y| = b.
If b = 0 there is one solution and if b>0 there are two solutions. hence not sufficient
Combination also yields the same result
Hence (E)
S1 a<0 => meaningless solution
S2 b >= 0 => |y| = b.
If b = 0 there is one solution and if b>0 there are two solutions. hence not sufficient
Combination also yields the same result
Hence (E)
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