Problem Solving

x, y, z are three consecutive integers such that three times the first is two more than twice the third one. What is the second integer ?

A) 8
B) 10
C) 12
D)16
E) 24


OA[spoiler]C
[/spoiler]

mitaliisrani wrote:x, y, z are three consecutive integers such that three times the first is two more than twice the third one. What is the second integer ?

A) 8
B) 10
C) 12
D)16
E) 24


OA[spoiler]C
[/spoiler]

Let's take x < y < z case, where y is x + 1 and z, x + 2.

Given that, 3 x = 2 z + 2

or 3 x = 2 (x + 2) + 2

or x = 6 and hence y = 7; no option

I guess something is missing, may be x, y, z are three consecutive EVEN integers, in that case...

Let's take x < y < z case again, where y is x + 2 and z, x + 4.

Given that, 3 x = 2 z + 2

or 3 x = 2 (x + 4) + 2

or x = 10 and hence y = [spoiler]12.

C[/spoiler]