Is xy > 0 ?
1. x/y < 0
2. x + y < 0
DS : xy > 0
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- harsh.champ
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I'm going to say E..
1. tells us that either x or y must be negative but both numbers cant be positive or negative - sufficient
2. tells us that when the numbers are added together they're still negative, so the negative number must be larger - sufficient
may not be right.. but i tried
1. tells us that either x or y must be negative but both numbers cant be positive or negative - sufficient
2. tells us that when the numbers are added together they're still negative, so the negative number must be larger - sufficient
may not be right.. but i tried
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- shashank.ism
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xy> 0 ----> either x and y both >0 or x and y both <0harsh.champ wrote:Is xy > 0 ?
1. x/y < 0
2. x + y < 0
St.1 : x/y <0 so x>0 and y<0 or x<0 and y>0 ------------------insufficient
St.2: x+y <0 so x<-y --> if y is +ve x/y <-1 ie. x is -ve
and if y i -ve x/y <1 i.e x might be +ve or -ve..
so insufficient
combined:
since st. 1 and the ques xy>0 are giving exactly opposite conditions
so st.1 and st.2 combined will give result which are not favorable so insufficient.........
Ans E
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- sumanr84
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I don't know why you concluded St1 is insufficient, even when u solved correctly though.shashank.ism wrote:xy> 0 ----> either x and y both >0 or x and y both <0harsh.champ wrote:Is xy > 0 ?
1. x/y < 0
2. x + y < 0
St.1 : x/y <0 so x>0 and y<0 or x<0 and y>0 ------------------insufficient
St.2: x+y <0 so x<-y --> if y is +ve x/y <-1 ie. x is -ve
and if y i -ve x/y <1 i.e x might be +ve or -ve..
so insufficient
combined:
since st. 1 and the ques xy>0 are giving exactly opposite conditions
so st.1 and st.2 combined will give result which are not favorable so insufficient.........
Ans E
When u know from ST 1 that either X or Y has to be less then 0 then result of XY will always be < 0 - Hence, sufficient.
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- shashank.ism
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SUMANR84 I think you are very correct in saying that xy <0 so it clearly says xy is not >0sumanr84 wrote: I don't know why you concluded St1 is insufficient, even when u solved correctly though.
When u know from ST 1 that either X or Y has to be less then 0 then result of XY will always be < 0 - Hence, sufficient.
Hence I should go with Ans AThanks suman..for pointing this mistake..
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hi all,
i guess the first one tells us that one of the number is -ve, so if that is the case, then XY has to be less than 0, then we know this case is sufficient to come to conclusion!-- hence sufficient
but in the 2nd case, x+y is less than 0, this can happen in 2 cases, 1st when both these nos. is -ve or when the larger of these 2 nos. is -ve. in this case.. since there are 2 conditions. we need to see for both the condition, do we get the same answer for our question which is XY>0 ... when the larger no. is -ve then, the answer is -ve.... when both the nos. are -ve then the answer is +ve.... hence we have 2 answers this case... n hence insufficient
so i guess only answer 1 is sufficient to answer... n answer 2 is not sufficient.
Victorious!
Rohan....
i guess the first one tells us that one of the number is -ve, so if that is the case, then XY has to be less than 0, then we know this case is sufficient to come to conclusion!-- hence sufficient
but in the 2nd case, x+y is less than 0, this can happen in 2 cases, 1st when both these nos. is -ve or when the larger of these 2 nos. is -ve. in this case.. since there are 2 conditions. we need to see for both the condition, do we get the same answer for our question which is XY>0 ... when the larger no. is -ve then, the answer is -ve.... when both the nos. are -ve then the answer is +ve.... hence we have 2 answers this case... n hence insufficient
so i guess only answer 1 is sufficient to answer... n answer 2 is not sufficient.
Victorious!
Rohan....
Victorious!
Rohan
Rohan