Is x2 < x - |y|?
1) y > x
2) x < 0
ANS IS D
DS
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Statement 1
RHS is always positive.
If y>x;
|y|>x
Therefore; x-|y| is always negative.
Hence RHS > LHS Sufficient
Statement 2:
x is negative;
RHS is positive
LHS is negative
Sufficient
Ans D
RHS is always positive.
If y>x;
|y|>x
Therefore; x-|y| is always negative.
Hence RHS > LHS Sufficient
Statement 2:
x is negative;
RHS is positive
LHS is negative
Sufficient
Ans D
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Shankar, I think your RHS and LHS may be flipped.
Greg Michnikov, Founder of GMAT Boost
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