DS

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 46
Joined: Thu Nov 22, 2007 6:32 am

DS

by ukr.net » Mon Dec 03, 2007 7:13 am
What is the value of k^2-k?
(1) The value of k - 1/k is 1.
(2) The value of 2k -1 is Square Root of 5

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient

ANS is D ???How to solve?

Legendary Member
Posts: 645
Joined: Wed Sep 05, 2007 4:37 am
Location: India
Thanked: 34 times
Followed by:5 members

by camitava » Mon Dec 03, 2007 7:17 am
ukr.net,
From stmt - 1,
k - 1/k = 1
so k^2 - 1 = k
From stmt - 2,
2k - 1 = sqrt(5)
So k = (sqrt(5) + 1)^2/2

So IMO D. - Have u got me ukr.net?
Correct me If I am wrong


Regards,

Amitava

Master | Next Rank: 500 Posts
Posts: 158
Joined: Mon Dec 03, 2007 8:32 am
Thanked: 7 times

by StarDust845 » Tue Dec 11, 2007 1:09 pm
Why is the answer D?

I see it this way.

From stmt (1) we get k^2 - k - 1 = 0

If you solve this, you get k = (1 + Sqrt(5))/2 or k = (1 - sqrt(5))/2
So the answer can't be A or D.

From stmt (2) we can solve for k which is k = (1 + sqrt(5))/2.

So answer MUST be B. What am I doing wrong?

Calista.

User avatar
Community Manager
Posts: 789
Joined: Sun Jan 28, 2007 3:51 pm
Location: Silicon valley, California
Thanked: 30 times
Followed by:1 members

by jayhawk2001 » Tue Dec 11, 2007 5:40 pm
StarDust845 wrote:Why is the answer D?

I see it this way.

From stmt (1) we get k^2 - k - 1 = 0

If you solve this, you get k = (1 + Sqrt(5))/2 or k = (1 - sqrt(5))/2
So the answer can't be A or D.
We don't have to solve for k here. Question asks for k^2 - k.