In the decimal representation of x, where 0 < x < 1, is the tenths digit of x nonzero?
(1) 16x is an integer.
(2) 8x is an integer.
I went with B, but the OA doesn't go with me:)
DS
This topic has expert replies
What is the OA? I also get .f2001290 wrote:In the decimal representation of x, where 0 < x < 1, is the tenths digit of x nonzero?
(1) 16x is an integer.
(2) 8x is an integer.
I went with B, but the OA doesn't go with me:)
Statement 1:
For 16x to be an integer, such that 0 < x < 1,
16x < 16,
16x = 15, in which case tenth's digit of x is NOT 0.
OR, 16x = 1, in which case tenth's digit of x is 0.
NS.
Statement 1:
For 8x to be an integer, such that 0 < x < 1,
8x < 8.
Say, 8x = 7, in which case tenth's digit of x is NOT 0.
OR, 8x = 1, in which case tenth's digit of x is NOT 0.
Sufficient.
-
- Senior | Next Rank: 100 Posts
- Posts: 98
- Joined: Mon Jun 11, 2007 10:32 pm
- Location: Mumbai
I think the answer is D.f2001290 wrote:In the decimal representation of x, where 0 < x < 1, is the tenths digit of x nonzero?
(1) 16x is an integer.
(2) 8x is an integer.
I went with B, but the OA doesn't go with me:)
(1) For 16x to be an integer, x has to be .5
(2) for 8x to be an integer, x again has to be .5
So tenth digit of x is a non zero.
Not necessarily.ratindasgupta wrote:I think the answer is D.f2001290 wrote:In the decimal representation of x, where 0 < x < 1, is the tenths digit of x nonzero?
(1) 16x is an integer.
(2) 8x is an integer.
I went with B, but the OA doesn't go with me:)
(1) For 16x to be an integer, x has to be .5
(2) for 8x to be an integer, x again has to be .5
So tenth digit of x is a non zero.
x = .3125 yields 16x as an integer also.... !!
x = .625 yields 8x as an integer also... !!
The answer is as explained above in my earlier post.