#m = ((m!)!). lf m is a positive integer, what is the
value of m ?
(1) 2! : (m - 1)!
(2 #m is six times the value of 5!
Can we cancel out the factorial from both sides?
DS question from princeton
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Did you write Statement 1 correctly?
Is Statement 1 what you are referring to with your question?
Is Statement 1 what you are referring to with your question?
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Hi, Actually this is a DS question and this was the only info given. It is from princeton. I can get the answer but im not sure if we can cancel out factorials from both side. ?Thanks
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In MOST cases, you can cancel out the factorials.rakaisraka wrote:Hi, Actually this is a DS question and this was the only info given. It is from princeton. I can get the answer but im not sure if we can cancel out factorials from both side. ?Thanks
That is, if k! = j!, then k = j
So, if 2! = (m - 1)!, then we can conclude that 2 = m-1, which means m = 3
HOWEVER, there is one proviso, which is based on the fact that 0! = 1! = 1
If either factorial is 0! or 1!, then the above rule does not apply.
For example, if we have (n - 2)! = 1!, then there are two possible solutions: n = 3 and n = 2
Cheers,
Brent
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I's assuming that statement 1 should read as follows:
Statement 1: 2! = (m - 1)!
This means that 2 = m-1, which means m = 3
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: #m is six times the value of 5!
So, (m!)! = (6)(5!)
(m!)! = (6)(5)(4)(3)(2)(1)
(m!)! =6!
So, m! = 6, which means m = 3
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Answer = D
Cheers,
Brent
Target question: What is the value of m?rakaisraka wrote:#m = ((m!)!). lf m is a positive integer, what is the
value of m ?
(1) 2! = (m - 1)!
(2 #m is six times the value of 5!
Statement 1: 2! = (m - 1)!
This means that 2 = m-1, which means m = 3
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: #m is six times the value of 5!
So, (m!)! = (6)(5!)
(m!)! = (6)(5)(4)(3)(2)(1)
(m!)! =6!
So, m! = 6, which means m = 3
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Answer = D
Cheers,
Brent
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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and equations ensures a solution.
#m = ((m!)!). lf m is a positive integer, what is the
value of m ?
(1) 2! = (m - 1)!
(2) #m is six times the value of 5!
==> In the original condition we have 1 variable (m) and we need 1 equation to match the number of variables and equations. Since we have 1 each in 1) and 2), D is likely the answer.
In actual calculation,
In case of 1), 2=m-1, m=3 sufficient and in case of 2), (m!)!=6(5!)=6!, m!=6=3*2*1, m=3 therefore is sufficient. Thus the answer is D.
For 95% of the questions that have 1) =2), D is the answer.
If you know our own innovative logics to find the answer, you don't need to actually solve the problem.
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#m = ((m!)!). lf m is a positive integer, what is the
value of m ?
(1) 2! = (m - 1)!
(2) #m is six times the value of 5!
==> In the original condition we have 1 variable (m) and we need 1 equation to match the number of variables and equations. Since we have 1 each in 1) and 2), D is likely the answer.
In actual calculation,
In case of 1), 2=m-1, m=3 sufficient and in case of 2), (m!)!=6(5!)=6!, m!=6=3*2*1, m=3 therefore is sufficient. Thus the answer is D.
For 95% of the questions that have 1) =2), D is the answer.
If you know our own innovative logics to find the answer, you don't need to actually solve the problem.
www.mathrevolution.com
l The one-and-only World's First Variable Approach for DS and IVY Approach for PS that allow anyone to easily solve GMAT math questions.
l The easy-to-use solutions. Math skills are totally irrelevant. Forget conventional ways of solving math questions.
l The most effective time management for GMAT math to date allowing you to solve 37 questions with 10 minutes to spare
l Hitting a score of 45 is very easy and points and 49-51 is also doable.
l Unlimited Access to over 120 free video lessons at https://www.mathrevolution.com/gmat/lesson
l Our advertising video at https://www.youtube.com/watch?v=R_Fki3_2vO8