Square S is inscribed in circle T. If the perimeter of S is 24, what is the circumference of T
1. 6 pi
2. 12 pi
3. 3 sqr (2pi)
4. 6 sqr (2pi)
5. 12 sqr (2 pi)
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circumf of circle
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g.shankaran
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bubbliiiiiiii
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cans
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let side of square=a
then 4a=24 -> a=6
diagonal = 6*root(2) = diameter of circle
thus circumference = diameter*pi
IMO D
then 4a=24 -> a=6
diagonal = 6*root(2) = diameter of circle
thus circumference = diameter*pi
IMO D
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MBA.Aspirant
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Perimeter = 24, side = 24 /4 = 6
Area of square = 36
1/2 Diagonal^2 = 36
Diagonal= root 72 = 6 root 2
radius = 3 root 2
Circumference = 2 TTr = 2* 3 root 2 * TT = 6 TT root2
Area of square = 36
1/2 Diagonal^2 = 36
Diagonal= root 72 = 6 root 2
radius = 3 root 2
Circumference = 2 TTr = 2* 3 root 2 * TT = 6 TT root2
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jainnikhil02
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[spoiler]6pi(root3)[/spoiler]
Nikhil K Jain
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Stuart@KaplanGMAT
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Great solution!MBA.Aspirant wrote:Perimeter = 24, side = 24 /4 = 6
Area of square = 36
1/2 Diagonal^2 = 36
Diagonal= root 72 = 6 root 2
radius = 3 root 2
Circumference = 2 TTr = 2* 3 root 2 * TT = 6 TT root2
A lesser known formula for the area of a square is:
area = (diagonal^2)/2
which is derived from the Pythagorean theorem (using 45/45/90 ratios).
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