A group of people participate in some curriculums, 20 of them practice Yoga, 10 study cooking, 12 study weaving, 3 of them study cooking only, 4 of them study both the cooking and yoga, 2 of them participate all curriculums. How many people study both cooking and weaving?
A.1 B.2 C.3 D.4 E.5
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Difficult Math Question #43 - Sets
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ajith
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The best way to do this is to draw a Venn Diagram800guy wrote:A group of people participate in some curriculums, 20 of them practice Yoga, 10 study cooking, 12 study weaving, 3 of them study cooking only, 4 of them study both the cooking and yoga, 2 of them participate all curriculums. How many people study both cooking and weaving?
A.1 B.2 C.3 D.4 E.5
Let me know if you need help on that. A search on the topic would certainly help.
Check out
https://www.beatthegmat.com/viewtopic.ph ... nn+diagram
Answer is E anyway
Always borrow money from a pessimist, he doesn't expect to be paid back.
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rajs.kumar
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Rajs - your approach is correct, however CnY = 2 (not 4) -- since you need the count for Cny only, you need to subtract 2 that is included as CnYnWrajs.kumar wrote:Answer is A.
CnW = 10 - (CnY) - (CnYnW) - only C = 10 - 4 - 2 - 3 = 1
Correct answer is 3
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rajs.kumar
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I assumed this "4 of them study both the cooking and yoga" to mean only cooking and yoga. If that is not the case I am wrong.shahmau wrote:Rajs - your approach is correct, however CnY = 2 (not 4) -- since you need the count for Cny only, you need to subtract 2 that is included as CnYnWrajs.kumar wrote:Answer is A.
CnW = 10 - (CnY) - (CnYnW) - only C = 10 - 4 - 2 - 3 = 1
Correct answer is 3
Can anyone explain the approach.
According to me the answer has to be >= 2(Ppl doing all 3 activities).
As far as my approach goes,
Since you have to find n(CnW)
n(Only C) = n(C) - n(CnY) - n(CnW) + n(CnWnY)
3 = 10 - 4 - n(CnW) + 2.
n(CnW) = 5.
Can anyone tell me where am i going wrong?
Regards,
Ali.
According to me the answer has to be >= 2(Ppl doing all 3 activities).
As far as my approach goes,
Since you have to find n(CnW)
n(Only C) = n(C) - n(CnY) - n(CnW) + n(CnWnY)
3 = 10 - 4 - n(CnW) + 2.
n(CnW) = 5.
Can anyone tell me where am i going wrong?
Regards,
Ali.
impossible is notthing....
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ajith
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You are absolutely right, nothing wrong in there IMOAalriy wrote:Can anyone explain the approach.
According to me the answer has to be >= 2(Ppl doing all 3 activities).
As far as my approach goes,
Since you have to find n(CnW)
n(Only C) = n(C) - n(CnY) - n(CnW) + n(CnWnY)
3 = 10 - 4 - n(CnW) + 2.
n(CnW) = 5.
Can anyone tell me where am i going wrong?
Regards,
Ali.
Always borrow money from a pessimist, he doesn't expect to be paid back.
