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## Difficult Math Problem #97 - Algebra

This topic has 6 member replies
800guy Master | Next Rank: 500 Posts
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#### Difficult Math Problem #97 - Algebra

Wed Feb 14, 2007 3:11 pm
Find the value of 1.1! + 2.2! + 3.3! + ......+n.n!

(1) n! +1
(2) (n+1)!
(3) (n+1)!-1
(4) (n+1)!+1
(5) None of these

oa coming when some people answer/explain. from diff math doc.

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gabriel Legendary Member
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Sun Feb 18, 2007 4:31 am
Mark Dabral wrote:
hi guys,

i am sure you know that this question is really way out of GMAT league.

S = 1(1!) + 2(2!) + 3(3!) + 4(4!) + ..... + (n-1)[(n-1)!] + n(n!)

S = [2-1](1!) + [3-1](2!) + [4-1](3!) + [5-1](4!) + ..... + (n-1)[(n-1)!] + [n+1 - 1](n!)

S = 2(1!) - 1! + 3(2!) - 2! + 4(3!) - 3! + 5(4!) - 4!+ ..... + n[(n-1)!] - (n-1)! + (n+1)(n!) - n!

S = 2! - 1! + 3! - 2! + 4! - 3! + 5! - 4!+ ..... + n! - (n-1)! + (n+1)! - n!

The terms 2!, 3!, 4!, and so on cancel out leaving only (n+1)! and the 1 term.

Therefore, S = (n+1)! - 1

Cheers,
Mark
hi there, great effort..... but u know what such q are much more easier than they seem..... make use of the answer choices...

in this particular q all that has to be done is choose a value for n .... eg let
n=2 so the series will be 1*1!+ 2*2! = 5.... now substitute n=2 in the answer choices... and u will find that only ( n+1 ) ! - 1 will give u a value 5 for n=2..... hope that helps

gabriel Legendary Member
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Sun Feb 18, 2007 4:35 am
[quote="banona"]Hy Kandelaki,
I wonder if you can use this general formula like :
Sn = n ( 2a1 + (n - 1)d ) / 2
I think it's only valid when adding consecutive numbers, like (1, 2,3,......n) or when numbers are equally far from each other; like consecutive evens ( 2; 4; 6; ......2n) or consecutives odds;
However, in our case 11! ; 22! ; 33!; ....... nn! are not consecutive numbers;

Can Mathematics tutors comment ?[/quote

yup....u r rite.... that is the formula for a AP...ie for a series with equally spaced elements...the formula cant be used in this case

gabriel Legendary Member
Joined
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Posted:
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Sun Feb 18, 2007 4:31 am
Mark Dabral wrote:
hi guys,

i am sure you know that this question is really way out of GMAT league.

S = 1(1!) + 2(2!) + 3(3!) + 4(4!) + ..... + (n-1)[(n-1)!] + n(n!)

S = [2-1](1!) + [3-1](2!) + [4-1](3!) + [5-1](4!) + ..... + (n-1)[(n-1)!] + [n+1 - 1](n!)

S = 2(1!) - 1! + 3(2!) - 2! + 4(3!) - 3! + 5(4!) - 4!+ ..... + n[(n-1)!] - (n-1)! + (n+1)(n!) - n!

S = 2! - 1! + 3! - 2! + 4! - 3! + 5! - 4!+ ..... + n! - (n-1)! + (n+1)! - n!

The terms 2!, 3!, 4!, and so on cancel out leaving only (n+1)! and the 1 term.

Therefore, S = (n+1)! - 1

Cheers,
Mark
hi there, great effort..... but u know what such q are much more easier than they seem..... make use of the answer choices...

in this particular q all that has to be done is choose a value for n .... eg let
n=2 so the series will be 1*1!+ 2*2! = 5.... now substitute n=2 in the answer choices... and u will find that only ( n+1 ) ! - 1 will give u a value 5 for n=2..... hope that helps

gabriel Legendary Member
Joined
20 Dec 2006
Posted:
986 messages
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Sun Feb 18, 2007 4:35 am
[quote="banona"]Hy Kandelaki,
I wonder if you can use this general formula like :
Sn = n ( 2a1 + (n - 1)d ) / 2
I think it's only valid when adding consecutive numbers, like (1, 2,3,......n) or when numbers are equally far from each other; like consecutive evens ( 2; 4; 6; ......2n) or consecutives odds;
However, in our case 11! ; 22! ; 33!; ....... nn! are not consecutive numbers;

Can Mathematics tutors comment ?[/quote

yup....u r rite.... that is the formula for a AP...ie for a series with equally spaced elements...the formula cant be used in this case

800guy Master | Next Rank: 500 Posts
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Fri Feb 16, 2007 11:27 am
oa:

1.1! + 2.2! + 3.3! + ......+n.n!
=1.1! + (3-1)2! + (4-1)3! +......+ ((n+1)-1) n!
=1.1!+3!-2!+4!-3!+.......+(n+1)!-n!

So it is (n+1)! -1 (Answer choice 4)

banona Senior | Next Rank: 100 Posts
Joined
30 Dec 2006
Posted:
38 messages
1
Thu Feb 15, 2007 7:06 am
Hy Kandelaki,
I wonder if you can use this general formula like :
Sn = n ( 2a1 + (n - 1)d ) / 2
I think it's only valid when adding consecutive numbers, like (1, 2,3,......n) or when numbers are equally far from each other; like consecutive evens ( 2; 4; 6; ......2n) or consecutives odds;
However, in our case 11! ; 22! ; 33!; ....... nn! are not consecutive numbers;

Can Mathematics tutors comment ?

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